Integrate (1-k^2 cos(x)^2)^(-3/2)

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The discussion focuses on integrating the function (1-k^2 cos(x)^2)^(-3/2) over the interval from 0 to π/2, where x is the variable and k is a constant. The user attempted integration by parts, setting u=1/(1-k^2 cos(x)^2) and v=1/(1-k^2 cos(x)^2)^(1/2), but encountered complex expressions that hindered further progress. The integration leads to results involving complete elliptic integrals of the second kind, indicating a need for advanced techniques in calculus.

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I want to integrate (1-k^2 cos(x)^2)^(-3/2) with lower limit 0 and upper limit pi/2, where x is the variable and k is the constant.
 
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nazmulislam said:
I want to integrate (1-k^2 cos(x)^2)^(-3/2) with lower limit 0 and upper limit pi/2, where x is the variable and k is the constant.

Hello nazmulislam. Welcome to PF !

According to the rules of this Forum, you have to show an attempt at the solution, before we can help you.
 
I tried to integrate by parts. Suppose u=1/(1-k^2 cos(x)^2) and v=1/(1-k^2 cos(x)^2)^(1/2). Then, I made dv/dx and tried to integrate u*(dv/dx) by parts. I did in this way because the results involve complete elliptic integrals of second kind. But I couldn't finish, because I got very complex expressions.
 

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