Integrate along curve, book has wrong answer?

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The discussion centers on the integral of a half circle with radius a, specifically $$\int_C y \, ds$$, where the book claims the answer is ##2a^2##. The user initially calculated the integral as $$\int_0^{\pi} a \sin(t) \, dt = 2a$$, questioning the book's answer. Another participant points out that the integral involves ds, not dt, leading to the realization that calculating ds was crucial for the correct solution. After addressing this, the user confirms that their understanding aligns with the book's answer.
Addez123
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Homework Statement
$$\int _C y ds$$
where C is determined by
$$x^2+y^2=a^2, y >= 0$$
Relevant Equations
Math
So it's basically a half circle with radius a.
y = asin(t)
$$\int_0^{\pi} asin(t) dt = -acos(t) |_0^{\pi} = 2a$$

The book says the answer is ##2a^2##, but maybe that's wrong?
 
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Addez123 said:
Homework Statement:: $$\int _C y ds$$
where C is determined by
$$x^2+y^2=a^2, y >= 0$$
Addez123 said:
So it's basically a half circle with radius a.
y = asin(t)
##\int_0^{\pi} asin(t) dt = -acos(t) |_0^{\pi} = 2a##
The book says the answer is ##2a^2##, but maybe that's wrong?
I believe the book's answer. Notice that the integral includes ds, not dt.
Note that ##ds = \sqrt{(dx/dt)^2 + (dy/dt)^2}dt##
 
Last edited:
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Likes vanhees71, Addez123 and FactChecker
Thanks! Calculating dS was what I was missing, now it checks out!
 

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