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[tex]\int[/tex] 9sin[tex]\sqrt{t+1}[/tex]

help please!!!! i dont even know where to start :[

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- Thread starter fiziksfun
- Start date

- #1

- 78

- 0

[tex]\int[/tex] 9sin[tex]\sqrt{t+1}[/tex]

help please!!!! i dont even know where to start :[

- #2

HallsofIvy

Science Advisor

Homework Helper

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First write it correctly:

[tex]\int 9 sin(\sqrt{t+1}) dt[/tex]

Make the obvious substitution [itex]u= \sqrt{t+1}= (t+1)^{1/2}[/itex] so that [itex]du= (1/2)(t+1)^{-1/2}dt[/itex] or 2udu= dt.

(Equivalently, u^{2}= t+ 1.)

That changes your integral to

[tex]9\int u sin(u)du[/tex]

and you can integrate that by parts.

[tex]\int 9 sin(\sqrt{t+1}) dt[/tex]

Make the obvious substitution [itex]u= \sqrt{t+1}= (t+1)^{1/2}[/itex] so that [itex]du= (1/2)(t+1)^{-1/2}dt[/itex] or 2udu= dt.

(Equivalently, u

That changes your integral to

[tex]9\int u sin(u)du[/tex]

and you can integrate that by parts.

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