- #1

- 78

- 0

[tex]\int[/tex] 9sin[tex]\sqrt{t+1}[/tex]

help please!!!! i dont even know where to start :[

- Thread starter fiziksfun
- Start date

- #1

- 78

- 0

[tex]\int[/tex] 9sin[tex]\sqrt{t+1}[/tex]

help please!!!! i dont even know where to start :[

- #2

HallsofIvy

Science Advisor

Homework Helper

- 41,833

- 963

First write it correctly:

[tex]\int 9 sin(\sqrt{t+1}) dt[/tex]

Make the obvious substitution [itex]u= \sqrt{t+1}= (t+1)^{1/2}[/itex] so that [itex]du= (1/2)(t+1)^{-1/2}dt[/itex] or 2udu= dt.

(Equivalently, u^{2}= t+ 1.)

That changes your integral to

[tex]9\int u sin(u)du[/tex]

and you can integrate that by parts.

[tex]\int 9 sin(\sqrt{t+1}) dt[/tex]

Make the obvious substitution [itex]u= \sqrt{t+1}= (t+1)^{1/2}[/itex] so that [itex]du= (1/2)(t+1)^{-1/2}dt[/itex] or 2udu= dt.

(Equivalently, u

That changes your integral to

[tex]9\int u sin(u)du[/tex]

and you can integrate that by parts.

Last edited by a moderator:

- Last Post

- Replies
- 2

- Views
- 675

- Last Post

- Replies
- 13

- Views
- 974

- Last Post

- Replies
- 3

- Views
- 814

- Last Post

- Replies
- 4

- Views
- 904

- Last Post

- Replies
- 10

- Views
- 1K

- Last Post

- Replies
- 2

- Views
- 1K

- Last Post

- Replies
- 3

- Views
- 2K

- Last Post

- Replies
- 10

- Views
- 1K

- Last Post

- Replies
- 1

- Views
- 801

- Last Post

- Replies
- 3

- Views
- 1K