Integrating 2t^2/(1+t^2)^2 with Trig Substitution

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Homework Statement



integrate 2t^(2)/(1+t^2)^(2)

Homework Equations



trig sub 1+tan^2(x)= sec^2(x)

The Attempt at a Solution


the attempted solution is attached.
 

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Your derivation is not correct and the method you follow is a bit complicated. Try integration by parts, ∫u'vdt=uv-∫uv'dt, with u'=2t/(1+t^2)^2 and v=t.

ehild
 
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If y = (1/3)t + C, then dy/dt = 1/3, which is clearly not even remotely close to the original integrand.
 
omg! i knowwwwwwwwwwwwwwwwww! i did it. that was so stupid of me. thank you.
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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