Integrating a Bessel Function with a Constant: Is This the Correct Approach?

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SUMMARY

The discussion focuses on the integration of the Bessel function J3/2(x) with respect to a constant 'a'. The integral ∫(J3/2(ax)/x^2)dx is evaluated, leading to the conclusion that a^2∫(J3/2(ax)/(ax)^2)dx equals a^2/2π. A substitution y = ax simplifies the integral, confirming that one of the 'a's cancels out, resulting in dx=dy/a. This method effectively resolves the integration challenge presented.

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Homework Statement



I've been given that the Bessel function

∫(J3/2(x)/x2)dx=1/2π (the integral goes from 0 to infinity).

Homework Equations



∫(J3/2(ax)/x2)dx,

where a is a constant.

The Attempt at a Solution



Is the following correct?

a2∫(J3/2(ax)/(ax)2)dx=a2/2π

(This is just a part of a triple integral. We are not asked nor expected to bother too much with the Bessel function, since it is not the focus of the problem).
 
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No, I think one of the 'a's goes away. Do the substitution again: y = ax. With a>0.
 
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dextercioby said:
No, I think one of the 'a's goes away. Do the substitution again: y = ax. With a>0.

Oh, of course. I then get dx=dy/a, which solves the problem for me. Thanks!
 

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