Integrating a Line Integral Along a Curve with Given Boundaries

Oakwater
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Homework Statement



∫(zdx+xdy+ydz)

along the curve C: x(t)= cos(t), y(t)= sin(t), z = 3t,

Boundaries are 0 and 2pi


Homework Equations



General integration and differentation.

The Attempt at a Solution


given the values I calculated that:

Using chain rule:

dx = -sintdt
dy = costdt
dz = 3dt

i then resubbed into the original equation to get:

∫(-3tsin(t)dt + cos^2(t)dt + 3sin(t)dt)

this is where I've got stuck, I attempted to integrate by parts the first term however it seems to get stuck in an endless loop, I'm not sure where to go from there.
 
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Why don't you show us your work. It may be a simple problem to fix.
 
The first and last terms of your integral should be easy to evaluate, the possibly tricky one is the middle term. The trick is to use the half-angle identity:
\cos^2 \theta = \frac{1 + \cos 2\theta}{2}
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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