Integrating Complex Functions in the Complex Plane

dykuma
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Homework Statement


Evaluate the following line integrals in the complex plane by direct integration.
upload_2016-11-13_21-56-9.png

Homework Equations


Z= x+i y = Cos(θ) +i Sin(θ) = e^i*θ

The Attempt at a Solution


I'm not sure how to evaluated this by hand. I tried using Z= x+i y = Cos(θ) +i Sin(θ), and evaluating the integral at dθ. However, I'm not sure how to change the bounds. It seems to me that point A starts at 2pi, and then point B is at 2pi + i *(infinity). what exactly does that mean?
 

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dykuma said:

Homework Statement


Evaluate the following line integrals in the complex plane by direct integration.
View attachment 108889

Homework Equations


Z= x+i y = Cos(θ) +i Sin(θ) = e^i*θ

The Attempt at a Solution


I'm not sure how to evaluated this by hand. I tried using Z= x+i y = Cos(θ) +i Sin(θ), and evaluating the integral at dθ. However, I'm not sure how to change the bounds. It seems to me that point A starts at 2pi, and then point B is at 2pi + i *(infinity). what exactly does that mean?
You overcomplicate the problem. Do the integral with respect to z, as if it was a common real number. Then substitute the limits for z, using that the upper limit means z=x+iy=2pi + iy, y-->infinity.
 
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ehild said:
You overcomplicate the problem. Do the integral with respect to z, as if it was a common real number.Then substitute the limits for z, using that the upper limit means z=x+iy=2pi + iy, y-->infinity.
I see. That is what I wanted to do at first. However, I was taken back by the complex part of the upper bound. I see now that I really over complicated that problem.

Thank you!
 

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There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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