Integrating e^(x^2)dx: Tips and Tricks for Solving Diff Eq Problems

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I'm doing a diff eq problem and I got stuck on the part where I have to integrate
e^(x^2)dx. I tried using substitution but that didn't work :confused: ... any ideas?
 
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There's a good reason why you're getting stuck - there is no simple expression for the integral you're trying to evaluate.
 
itzela said:
I'm doing a diff eq problem and I got stuck on the part where I have to integrate
e^(x^2)dx. I tried using substitution but that didn't work :confused: ... any ideas?


if it is definite integral you can evaluate by double integral and transformation to polar. if it is indefinite, a good way to evaluate it is integrate its polynomial expansion. but itself doesn't have an antiderivative
 
Got it =) Thanks for pointing me in that direction.
 
Prove $$\int\limits_0^{\sqrt2/4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx = \frac{\pi^2}{8}.$$ Let $$I = \int\limits_0^{\sqrt 2 / 4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx. \tag{1}$$ The representation integral of ##\arcsin## is $$\arcsin u = \int\limits_{0}^{1} \frac{\mathrm dt}{\sqrt{1-t^2}}, \qquad 0 \leqslant u \leqslant 1.$$ Plugging identity above into ##(1)## with ##u...
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