Is -t the Correct Integrating Factor for this Diff Eq?

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[SOLVED] Integrating Factor Diff Eqs

Homework Statement



g ' - g/t = t e^t

I'm trying to solve this, but I seem to have run into a problem, according to my book the integrating factor is 1/t, however I believe that it is -t


Homework Equations





The Attempt at a Solution



e^int(-1/t dt) = e^(-lnt) = -t
That is how I found the solution to all the problems requiring an integrating factor before however this situation seems to be different... Do I have the equation in the right form to find the integrating factor?
 
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e^{-\ln t}=e^{\ln t^{-1}}=\frac{1}{t}
 
Prove $$\int\limits_0^{\sqrt2/4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx = \frac{\pi^2}{8}.$$ Let $$I = \int\limits_0^{\sqrt 2 / 4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx. \tag{1}$$ The representation integral of ##\arcsin## is $$\arcsin u = \int\limits_{0}^{1} \frac{\mathrm dt}{\sqrt{1-t^2}}, \qquad 0 \leqslant u \leqslant 1.$$ Plugging identity above into ##(1)## with ##u...
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