# Integrating gravity(g)= -9.8m/s

1. Sep 25, 2004

### Alem2000

correct me if im wrong....

By integrating gravity(g)= -9.8m/s....you get the motion equations with constant acceleration

I didnt know how to set the limits of the integral...LATEX IS TUFF
$$d\vec{a}=(-g)dt$$ 1

$$\int_{\vec{V}_0}^{\vec{V}}dv=\int_{t_0}^{t_1}{-g}dt$$ 2

$$\Delta{\vec{v}}=(-g)t$$ 3

$$\vec{v}dt=d\vec{r}$$ 4

$$\d\vec{r}=(\vec{v}_0+(-g)t)dt$$ 5

$$\intd\vec{r}=\int(\vec{v}_0+(-g)tdt$$ 6

$$\Delta\vec{r}=\vec{v}_0t+1/2(-g)t^2$$ 7

$$\Delta{\vec{v}}=\int{\vec{v}_0}dt$$ 8

HOLD ON A SEC IM TRYN TO LATEX...Can anyone prove the force equations?

Last edited: Sep 25, 2004
2. Sep 25, 2004

### Tide

Are you talking about Newton the physicist or Newton the mathematician?

Physics: force = mass times acceleration or change in momentum per unit time

acceleration = time rate of change of velocity

Mathematics: $a = \frac {dv}{dt}$

3. Sep 25, 2004

### Alem2000

Gravity

Did I make some mistakes...?..i think i fixed them all. Can anyone show how to derive Torqu?

$$\Delta{\vec{v}}=(-g)t$$ 3

$$\vec{v}dt=d\vec{r}$$ 4

$$d\vec{r}=(\vec{v}_0+(-g)t)dt$$ 5

$$\intd\vec{r}=\int(\vec{v}_0+(-g)tdt$$ 6

$$\Delta\vec{r}=\vec{v}_0t+1/2(-g)t^2$$ 7

$$\Delta{\vec{v}}=\int{\vec{v}_0}dt$$ 8

Last edited: Sep 25, 2004
4. Sep 25, 2004

### Alem2000

Oooops I ment to put that on the physics posts not calculus

5. Oct 30, 2004

### Alem2000

how did he figure it out..experiment?

Last edited: Oct 30, 2004
6. Nov 1, 2004

### drcrabs

No English!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

7. Nov 1, 2004

### Gokul43201

Staff Emeritus
Alem, there appears to be a problem with your line #8.