Integrating gravity(g)= -9.8m/s

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In summary, the conversation is discussing the integration of gravity and its relation to motion equations with constant acceleration. The conversation also briefly mentions using LATEX and asks for help in deriving torque and the force equations.
  • #1
Alem2000
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correct me if I am wrong...

By integrating gravity(g)= -9.8m/s...you get the motion equations with constant acceleration

I didnt know how to set the limits of the integral...LATEX IS TUFF
[tex]d\vec{a}=(-g)dt[/tex] 1

[tex]\int_{\vec{V}_0}^{\vec{V}}dv=\int_{t_0}^{t_1}{-g}dt[/tex] 2

[tex]\Delta{\vec{v}}=(-g)t[/tex] 3

[tex]\vec{v}dt=d\vec{r}[/tex] 4

[tex]\d\vec{r}=(\vec{v}_0+(-g)t)dt[/tex] 5

[tex]\intd\vec{r}=\int(\vec{v}_0+(-g)tdt[/tex] 6

[tex]\Delta\vec{r}=\vec{v}_0t+1/2(-g)t^2[/tex] 7

[tex]\Delta{\vec{v}}=\int{\vec{v}_0}dt[/tex] 8


HOLD ON A SEC IM TRYN TO LATEX...Can anyone prove the force equations?

HI merons dad
 
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  • #2
Are you talking about Newton the physicist or Newton the mathematician?

Physics: force = mass times acceleration or change in momentum per unit time

acceleration = time rate of change of velocity

Mathematics: [itex]a = \frac {dv}{dt}[/itex]
 
  • #3
Gravity

Did I make some mistakes...?..i think i fixed them all. Can anyone show how to derive Torqu?

[tex]\Delta{\vec{v}}=(-g)t[/tex] 3

[tex]\vec{v}dt=d\vec{r}[/tex] 4

[tex]d\vec{r}=(\vec{v}_0+(-g)t)dt[/tex] 5

[tex]\intd\vec{r}=\int(\vec{v}_0+(-g)tdt[/tex] 6

[tex]\Delta\vec{r}=\vec{v}_0t+1/2(-g)t^2[/tex] 7

[tex]\Delta{\vec{v}}=\int{\vec{v}_0}dt[/tex] 8
 
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  • #4
Oooops I ment to put that on the physics posts not calculus :frown: :frown:
 
  • #5
how did he figure it out..experiment?
 
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  • #6
No English!
 
  • #7
Alem, there appears to be a problem with your line #8.
 

Related to Integrating gravity(g)= -9.8m/s

What does "integrating gravity" mean?

Integrating gravity refers to incorporating the effects of gravity into a mathematical model or equation. This allows for more accurate predictions and understanding of physical phenomena.

What is the significance of the value -9.8m/s for gravity?

The value of -9.8m/s is the standard acceleration due to gravity on Earth. This means that for every second an object falls, its velocity will increase by 9.8 meters per second in the downward direction.

How does integrating gravity affect objects in motion?

Integrating gravity into equations allows for the calculation of an object's trajectory and velocity, taking into account the constant acceleration due to gravity. This is especially important for objects in free fall or orbit around a larger body.

Is the value of -9.8m/s for gravity constant?

The value of -9.8m/s for gravity is a constant on Earth, but it may vary slightly in different locations or on different planets due to variations in their mass and size.

How does integrating gravity relate to Newton's laws of motion?

Integrating gravity is essential for understanding and applying Newton's laws of motion, as gravity is a fundamental force that affects the motion of all objects. Without taking gravity into account, Newton's laws would not accurately describe the behavior of objects in the real world.

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