fermio Messages 38 Reaction score 0 Thread starter Jan 20, 2008 #1 How to integrate integral [tex]\int\frac{8}{x^2+4}dx[/tex] ?
arildno Science Advisor Homework Helper Gold Member Dearly Missed Messages 10,165 Reaction score 138 Jan 20, 2008 #2 Rewrite it in the form: [tex]\int\frac{2dx}{(\frac{x}{2})^{2}+1}[/tex] See if that helps you.
HallsofIvy Science Advisor Homework Helper Messages 42,895 Reaction score 983 Jan 20, 2008 #3 The derivative of arctan(x) is [tex]\frac{d tan^{-1}(x)}{dx}= \frac{1}{x^2+ 1}[/tex] Does that help?
fermio Messages 38 Reaction score 0 Jan 20, 2008 #4 [tex]\int\frac{8}{x^2+4}dx=\int\frac{2dx}{(\frac{x}{2})^2+1}=\int\frac{4d(\frac{x}{2})}{(\frac{x}{2})^2+1}=4\arctan\frac{x}{2}[/tex] [tex]d(\frac{x}{2})=\frac{1}{2}dx[/tex] [tex]dx=2d(\frac{x}{2})[/tex]
[tex]\int\frac{8}{x^2+4}dx=\int\frac{2dx}{(\frac{x}{2})^2+1}=\int\frac{4d(\frac{x}{2})}{(\frac{x}{2})^2+1}=4\arctan\frac{x}{2}[/tex] [tex]d(\frac{x}{2})=\frac{1}{2}dx[/tex] [tex]dx=2d(\frac{x}{2})[/tex]