Integrating Rational Functions with Trigonometric Substitutions

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How to integrate integral
[tex]\int\frac{8}{x^2+4}dx[/tex]
?
 
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Rewrite it in the form:
[tex]\int\frac{2dx}{(\frac{x}{2})^{2}+1}[/tex]
See if that helps you.
 
The derivative of arctan(x) is
[tex]\frac{d tan^{-1}(x)}{dx}= \frac{1}{x^2+ 1}[/tex]

Does that help?
 
[tex]\int\frac{8}{x^2+4}dx=\int\frac{2dx}{(\frac{x}{2})^2+1}=\int\frac{4d(\frac{x}{2})}{(\frac{x}{2})^2+1}=4\arctan\frac{x}{2}[/tex]
[tex]d(\frac{x}{2})=\frac{1}{2}dx[/tex]
[tex]dx=2d(\frac{x}{2})[/tex]