Integrating Sin(6θ): Am I Close?

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Homework Statement



\int\sin(6\theta) d\theta


Homework Equations





The Attempt at a Solution



\int6\cos6\theta

Am I close?
 
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If it helps do a u-sub where u=6theta

Or you could think of it like this:

If we take the derivative of \frac{d}{d \theta}(-cos(\theta)) = sin(\theta). That's sort of like the anti-derivative which you seek.

If we take the derivative of \frac{d}{d \theta}(-cos(6 \theta)) = 6sin(6 \theta).

So from there it's easy to see that\int\sin(6\theta) d\theta = \frac{-cos(6\theta)}{6}
 
errr...

\frac{-\cos6\theta}{6}
 
thanks :)
 
Yeah looks right^^
 
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