Integration by partial fractions

AI Thread Summary
The discussion focuses on solving the integral of (x^2-1)/((x+2)^2(x+3)) using partial fraction decomposition. The user initially breaks the expression into components A/(x+2)^2, Bx+C/(x+2), and D/(x+3), but struggles with setting up the system of equations. They suggest multiplying through by (x+2)^2(x+3) and substituting x=-3 to simplify the problem. After expanding and grouping terms, they derive values for A, B, C, and D, ultimately finding A=0, D=8, C=-7, and B=3. The conversation highlights the importance of careful notation and organization in solving such integrals.
Spectre32
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Ok this is the Integral:

(x^2-1)/((x+2)^2(x+3))


Now What i did is break this up into the A + B+C ...etc etc and i came to this:


A/(x+2)^2 + Bx+C/(x+2) + D/X+3... Now i know i got to use systems of equations but I've been working on this for like 40 mins and i still can't get it straight. If anyone can help me power through this i should then be set.
 
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multiply everything by (x+2)^2(x+3). After that if you set x=-3 than everything will cancel out except D, which you can than solve for. If you set x=-3 you can create an equation that you can solve for later.

Here comes the annoying part. Expand everything out. Than group everything that has the same degree polynomial (ie group everything that is x^2, x^1, x^0) and factor out the x term. You'll notice that all of this must be equal to x^2-1. Thus, whatever you have infront of x^2 must be 1. Whatever you have infront of x must be 0. Everything else would have to be -1. You have a bunch of equations and 3 more variables to solve for. Enjoy.

i got A=0, D=8, C=-7, B=3.
 
(Note to Spectre: you need to be more careful about using parentheses)

Why do you have (Bx + C) / (x + 2)?
 
Its supposed to be (Ax + B) / (x + 2)^2 + C/(x + 2) + D/(x + 3)...
 
Why do you have (Ax + B) / (x + 2)^2?
 
Yeah I know... i broke it up and then everything went to plan.. thanks.
 
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