Integration by partial fractions.

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Homework Help Overview

The discussion revolves around the integration of a rational function using partial fractions, specifically the integral of (2x^2 + x + 9) / ((9x + 1)(x^2 + 9)). Participants are exploring the decomposition of the integrand into simpler fractions for integration purposes.

Discussion Character

  • Exploratory, Assumption checking, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the decomposition of the integrand into partial fractions, questioning the accuracy of their coefficients A, B, and C. There is a focus on verifying the correctness of the fractions and the resulting equations derived from multiplying by the denominator.

Discussion Status

The conversation is ongoing, with participants sharing their attempts at solving for the coefficients and expressing uncertainty about their results. Some guidance has been provided regarding setting values for x to simplify the solving process, but no consensus has been reached on the correct values for A, B, and C.

Contextual Notes

Participants note that calculators are not allowed, and the problem originates from an old exam, which may contribute to the complexity and unusual nature of the coefficients they are encountering.

Econometricia
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1.\int2x^2+x+9/(9x+1)(x^2+9) dx

2. (A/9x+1) + [(Bx + C ) / (x^2 + 9)]

I get the worst numbers when I solve the system. The question is from an old exam and calculators are not allowed. Am I doing something wrong or is there another way to integrate this?
 
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Are you sure of the numbers you are getting? IOW, did you check to make sure that your two separate fractions add up to the larger one?
 
Yes, I used a solver to check my work because it did not seem right. I am fairly sure the fractions are broken up properly as well. =(
 
Yes, your decomposition is fine. Out of curiosity, what did you get for A, B, and C?
 
a=37/41 b=5/41 c = 7/41 I mean its not that outrageous I guess. I guess I just assume I do things wrong lol.
 
Just to make sure, the integrand is

\frac{2x^2+x+9}{(9x+1)(x^2+9)}

and not

2x^2+x+\frac{9}{(9x+1)(x^2+9)}

right? In either case, your values for A, B, and C aren't correct. If the first version of the integrand is the right one, the coefficients come out even less pretty.
 
Yes the first version is correct. -.- Do you have any suggestions?
 
your partial fractions expansion is:

<br /> \frac{A}{9 x + 1} + \frac{B \, x + C}{x^{2} + 9}<br />

Multiplying both sides by (9 x + 1)(x^{2} + 9) and comparing similar terms, you will get 3 equations for 3 unknowns.
 
I get the following system:

<br /> \left\{<br /> \begin{array}{rcl}<br /> 9 A + C &amp; = &amp; 9 \\<br /> <br /> B + 9 C &amp; = &amp; 1 \\<br /> <br /> A + 9 B &amp; = &amp; 2<br /> \end{array} \right.<br />
 
  • #10
After you multiply by the denominator, I'd set x=-1/9, which allows you to solve for A, then use the equations Dickfore got to solve for B and C.
 
  • #11
Yeah... It must be some type of cruel joke.
 
  • #12
The denominators for the solutions are equal to the number of days in a year.
 
  • #13
361/365 41/365 36/365
It was on an old exam lol. I hope there's nothing like that on our exam =O.
 

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