Integration by parts difficulties

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SUMMARY

The discussion centers on the application of integration by parts as presented in Acheson's book "From Calculus to Chaos," specifically equation 8.6. The user struggles with the transformation of the integral involving the terms m∫(ẏAη - gη) dt into the form m[ẏAη]t1t2 - m∫(ẏA + g)η dt. The key to solving this problem lies in correctly identifying u and dv for integration by parts, where u = ẏA and dv = dη. The user notes that only the first term, ẏAη, was integrated by parts, while the term gη was not.

PREREQUISITES
  • Understanding of integration by parts formula: ∫u dv = uv - ∫v du
  • Familiarity with calculus concepts, particularly derivatives and integrals
  • Knowledge of the notation used in calculus, such as dot notation for derivatives
  • Experience with Acheson's "From Calculus to Chaos" for context
NEXT STEPS
  • Review the integration by parts technique in calculus
  • Study the specific example in Acheson's "From Calculus to Chaos" to understand its application
  • Practice similar integration problems involving multiple terms
  • Explore advanced calculus topics that utilize integration by parts in physics applications
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Students and educators in mathematics, particularly those studying calculus and integration techniques, as well as anyone seeking to deepen their understanding of integration by parts in applied contexts.

falcao
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Just working through a problem Acheson's book (From Calculus to Chaos) if anyone knows it.. eq 8.6 in this book..

As he's working through the problem he makes the step of this:


<br /> m\int_{t_{1} }^{t_{2}} \left( \dot{y}_{\scriptscriptstyle A }\dot{\eta} - g\eta \right)\,dt <br /> (1)

to

m\left[\dot{y}_{\scriptscriptstyle A} \eta\right]_{t_{1}}^{t_{2}} -<br /> m\int_{t_{1}}^{t_{2}}\left(\ddot{y}_{\scriptscriptstyle A} + g\right)\eta\,dt<br /> (2)

... using integration by parts.

Now, I've been stuck on it for a little while and I can't really figure it out.. I tried 'taking out' the \eta but had no luck, if anyone had any suggestions of what to let == dv and what to let == u in the formula it would probably sort me out!
\int u\,dv = uv - \int v\,du<br />
Thanks in advance! (ps. I can post further workings if necessary)
 
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He only did integration by parts on the first term in the integral, the \dot{y}_A\dot{\eta} term. The g\eta term was not integrated by parts. u = \dot{y}_A, dv = \dot{\eta}dt.
 
Mute said:
He only did integration by parts on the first term in the integral, the \dot{y}_A\dot{\eta} term. The g\eta term was not integrated by parts. u = \dot{y}_A, dv = \dot{\eta}dt.
sorry, my bad, although I probably wouldn't have realized if I looked at it for a full day! :redface:thanks for your help
 

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