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Integration by parts help just the beginning part for this one

  • Thread starter camboguy
  • Start date
  • #1
36
0

Homework Statement


intergral from pi to 0.
of
(sin(3t)dt)^4






The Attempt at a Solution



okay so i know how to do this but when i tried substitution putting 3t=u and (1/3)du= dt i always came with the the wrong coefficient at the end with the answer and so i would multiply it wrong. but then when i do not use u/du substitution everything works well? why is that? what is the difference? and im using u/du substitution improperly or something?
 

Answers and Replies

  • #2
378
2
Are you correctly changing the limits?
 
  • #3
36
0
i didn't need to change it because i just plugged back in the variables u with 3t. just wondering it should be correct even if i substitute right?
 

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