Integration by Parts homework assistance

In summary, the problem involves finding the integral of x3e5x2 dx using the formula uv-∫vdv. By expressing the problem as ∫ (x^2).(xe^{5x^2})dx and using u-substitution, the solution can be found by setting U = x2, dU = 2x, dv = xe5x2, and V = 1/10e5x2. The final answer is (x2)(1/10e5x2) - ∫(1/10e5x2)2x dx.
  • #1
AryRezvani
67
0

Homework Statement



∫x3e5x2 dx

Homework Equations



uv-∫vdv

The Attempt at a Solution



I've tried this one a few times, but keep getting answers that are just out there. Could someone, if possible, work out just the beginning.
 
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  • #2
AryRezvani said:

Homework Statement



∫x3e5x2 dx

Homework Equations



uv-∫vdv

The Attempt at a Solution



I've tried this one a few times, but keep getting answers that are just out there. Could someone, if possible, work out just the beginning.

OK, just one hint to get you started. You should start by expressing the problem as:

[tex]\int (x^2).(xe^{5x^2})dx[/tex]
 
  • #3
Hmm okay, got it.

So let's say U = x2
dU = 2x

dv = xe5x2
V=1/10e5x2

Then, plug into the equation, and you get...

(x2)(1/10e5x2) - ∫(1/10e5x2)2x dx

EDIT: Just got it, thanks a lot for your time :).
 
Last edited:
  • #4
AryRezvani said:
Hmm okay, got it.

So let's say U = x2
dU = 2x

dv = xe5x2
V=1/10e5x2

Then, plug into the equation, and you get...

(x2)(1/10e5x2) - ∫(1/10e5x2)2x dx

EDIT: Just got it, thanks a lot for your time :).
No worries. :smile:
 

What is integration by parts?

Integration by parts is a method used in calculus to find the integral of a product of two functions. It is based on the product rule of differentiation and allows us to solve integrals that cannot be solved by other methods.

When should I use integration by parts?

Integration by parts should be used when the integral involves a product of two functions, and other methods like substitution or trigonometric identities do not work. It is also useful when trying to simplify an integral that involves a function multiplied by its derivative.

How do I choose which function to integrate and which one to differentiate?

The general rule for choosing which function to integrate and which one to differentiate is called the "LIATE" rule. LIATE stands for logarithmic, inverse trigonometric, algebraic, trigonometric, and exponential functions. In general, the function that falls first in this list should be chosen as the function to integrate, and the one that comes later should be chosen as the one to differentiate.

What are the steps for solving an integral using integration by parts?

The steps for solving an integral using integration by parts are as follows: 1) Identify the two functions in the integral and label them as u and dv. 2) Use the product rule to find the derivative of u and integrate dv. 3) Plug in the values for u, du, v, and dv in the integration by parts formula: ∫ u dv = uv - ∫ v du. 4) Simplify the integral on the right-hand side and solve for the original integral. 5) If necessary, use the integration by parts formula again on the new integral until it can be solved.

Are there any tips or tricks for solving integration by parts problems?

One tip for solving integration by parts problems is to choose u and dv carefully. It is often helpful to choose u as a function that becomes simpler when differentiated, and dv as a function that becomes simpler when integrated. Another helpful tip is to check your answer by differentiating the result of the integration by parts process to see if it matches the original function.

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