Integration by parts involving an unknown function

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SUMMARY

The discussion centers on the application of integration by parts to transition from equation (2.13) to (2.14) involving an unknown function, σ(τ). The integral ∫τ0tσ(τ)dτ is evaluated using integration by parts, resulting in the expression σ(t)t - σ(τ00 - ∫τ0tτ̇σ(τ)dτ. A key insight is that the term σ(t)t can be rewritten as an integral, allowing the variable t to be treated as a constant during integration. This manipulation clarifies why equation (2.14) does not depend on σ(t).

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sara_87
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Homework Statement



I have attached a picture including 2 equations: (2.13) and (2.14)
I don't understand how they got from (2.13) to (2.14) using integration by parts

Homework Equations





The Attempt at a Solution


For the integral:
[itex]\int_{\tau_0}^t\sigma(\tau)d\tau= \left[\sigma(\tau)\tau\right]_{\tau_0}^{t}-\int_{\tau_0}^t\dot{\sigma}(\tau)\tau d\tau[/itex]
by assuming [itex]u=\sigma(\tau)[/itex] and [itex]v'=1[/itex] for integration by parts.
This gives:
[itex]\sigma(t)t-\sigma(\tau_0)\tau_0-\int_{\tau_0}^{t}\tau\dot{\sigma}(\tau)d\tau[/itex]

So, even when we do combine this result with the other terms in equation (2.13), I don't understand how (2.14) does not depend on [itex]\sigma(t)[/itex].

Thank you in advance for any ideas.
 

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Hi sara_87! :)

One of your terms is ##\sigma(t)t##.
You can rewrite that as an integral:

$$t \sigma(t)+C=t \int_{\tau_0}^t \dot\sigma(\tau)d\tau=\int_{\tau_0}^t t \dot\sigma(\tau)d\tau$$

The variable t can be moved into the integral, since you do not integrate over t, so t behaves like a constant with respect to integration.
 

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