Integration by parts of a function

apiwowar
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the function is c = 15te-.2t

the goal is to integrate it from t = 0 to t = 3

so to set up the integral i took out the 15 first so i got:

15 * integral from 0 to 3 of t*e-.2t

i set u = t and so du = dt
dv = e-.2tdt so v= -5e-.2t

so following the integration by parts formula i got:

15(-5*e-.2t + 5* integral of e-.2tdt

then after integrating the second part i got

15(-5e-.2t - 25e-.2t) evaluated from 0 to 3

when evaluated i got

(-123/4826181 - 205.8043635)-(-75-375) = 120.7130184

but that's wrong,

anyone have any hints or sees any mistakes that i made?

thanks
 
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apiwowar said:
the function is c = 15te-.2t

the goal is to integrate it from t = 0 to t = 3

so to set up the integral i took out the 15 first so i got:

15 * integral from 0 to 3 of t*e-.2t

i set u = t and so du = dt
dv = e-.2tdt so v= -5e-.2t

so following the integration by parts formula i got:

15(-5*e-.2t + 5* integral of e-.2tdt
s

this should be

15(-5te-0.2t+5∫e-.2tdt
 
your right, that's just a typo, i had the t there in my calculations
 
it looks like you did it correct, is your answer supposed to be in terms of e?
 
i don't think so, it just asks for the exact answer
 
apiwowar said:
i don't think so, it just asks for the exact answer

Then you need to write it in terms of the constant e. So recalculate the answer, just not using a calculator.
 
so just leave it as with the base e but calculate the exponents of e?
 
apiwowar said:
so just leave it as with the base e but calculate the exponents of e?

Yes.
 
ok, thanks alot
 
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