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fashion_fever
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Homework Statement
evaluate:
higher limit of 36
lower limit of 0 (36+3x)^1/2 dx
Homework Equations
i thought of using subsititution?
The Attempt at a Solution
g(x)=36+3x
g'(x)=3
when x=0, u=36+3(0)=36
when x=36, u=36+3(36)=144
from lower limit of 36 to higher limit of 144
3(u)^1/2 du= 3(2/3)u^3/2 + C
substitute 36+3x back into u, i get: 2(36+3x)^3/2 + C
=[2(36+3(144))^3/2) + C ] - [ 2(36+3(36))^3/2] + C
= 2(468)^3/2 - 3456 + C
is this correct??
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