Mastering Integration: Strategies for Solving Tricky Equations

  • Thread starter Thread starter kring_c14
  • Start date Start date
  • Tags Tags
    Lost
kring_c14
Messages
76
Reaction score
0
integration--im lost

Homework Statement


how do you integrate this one

\int sint cosnt dti tried using this identity 1/2 [sin(t-nt) + sin (t-nt)]

then i got stuck so i used another identity again
sin (t^{+}_{-}nt)= sintcosnt^{+}_{-}costsinnt

the result is the original equation..

to sum it all, I am hopelessly stuck
 
Physics news on Phys.org
uhmmm hi! i don't really know what to do...and blood is dripping out of my nose! waaaah! *dramatic*
 
A sure fire way that doesn't take a lot of brains is to use identities like cos(x)=(exp(ix)-exp(-ix))/2 (deMoivre). You can convert the whole thing to exponentials and they are easy.
 
kring_c14 said:

Homework Statement


how do you integrate this one

\int sint cosnt dt


i tried using this identity 1/2 [sin(t-nt) + sin (t-nt)]


Well, this identity doesn't look right to me.

then i got stuck so i used another identity again
sin (t^{+}_{-}nt)= sintcosnt^{+}_{-}costsinnt

the result is the original equation..

to sum it all, I am hopelessly stuck

Nope, you don't need to expand it. It'll give you the original expression. Hint: Can you simplify: t - nt, and t + nt?
 
kring_c14 said:

Homework Statement


i tried using this identity 1/2 [sin(t-nt) + sin (t-nt)]

1/2 [sin(t+nt) + sin (t-nt)]--->sorry, got it wrong..this ones correct
 
VietDao29 said:
Nope, you don't need to expand it. It'll give you the original expression. Hint: Can you simplify: t - nt, and t + nt?

that gives me t^{2}-n^{2}t^{2}

but where would i plug this equation

im really not that good at manipulating equation..havent learned trigonometry at heart
 
kring_c14 said:
that gives me t^{2}-n^{2}t^{2}

but where would i plug this equation

im really not that good at manipulating equation..havent learned trigonometry at heart

Ack. >"< No, that's not correct at all.

Well, it's not that hard. We have:

sin(t + nt) = sin[(n + 1)t]. Which can be easily integrated. Simple, eh? :)

You can do the same to the other one. Can you go from here? :)
 
aw sorrryyy, lol...just being my dumb self again..shame on me.. lol
thank you very much!
 
Back
Top