- #1

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may i know how to solve this ques:

integra (3x+1) / (2x^2 - 2x +3 )

pls help.....

integra (3x+1) / (2x^2 - 2x +3 )

pls help.....

- Thread starter teng125
- Start date

- #1

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may i know how to solve this ques:

integra (3x+1) / (2x^2 - 2x +3 )

pls help.....

integra (3x+1) / (2x^2 - 2x +3 )

pls help.....

- #2

TD

Homework Helper

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- #3

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for the second part i got 3-x /(2x^2 - 2x +3)

may i know how to solve for inverse tangent??

may i know how to solve for inverse tangent??

- #4

TD

Homework Helper

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The derivative of the denominator is 4x-2, it should look like this:

[tex]\int {\frac{{3x + 1}}{{2x^2 - 2x + 3}}dx} = \frac{3}{4}\int {\frac{{4x - 2 + 10/3}}{{2x^2 - 2x + 3}}dx} = \frac{3}{4}\int {\frac{{4x - 2}}{{2x^2 - 2x + 3}}dx} + \frac{{10}}{3}\frac{3}{4}\int {\frac{1}{{2x^2 - 2x + 3}}dx} [/tex]

- #5

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okok....got it...thanx

- #6

TD

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