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## Homework Statement

what is the integral of ln(e

^{2x-1}) dx

**2. The attempt at a solution**

I got

u= ln(e

^{2x-1})

du = 2e

^{2x-1}\ e

^{2x-1}

du = 2 dx

1/2(integral of u du)

1/2 ln (e

^{2x-1}) +c

=

1/4 [ln (e

^{2x-1})]

^{2}+ c

Could you please let me know if this is correct? I dont know how to integrate ln

thanks again

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