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kill00
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Homework Statement
what is the integral of ln(e2x-1) dx
2. The attempt at a solution
I got
u= ln(e2x-1)
du = 2e2x-1 \ e2x-1
du = 2 dx
1/2(integral of u du)
1/2 ln (e2x-1 ) +c
=
1/4 [ln (e2x-1 )]2 + c
Could you please let me know if this is correct? I don't know how to integrate ln
thanks again
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