- #1

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## Homework Statement

Alright heres the problem. Also it is a definite integral from

**A=0 and b = 1**

[tex]\int (x^7)(x^4-1)^{1/3}[/tex]

Any help is good.

- Thread starter jordan123
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- #1

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Alright heres the problem. Also it is a definite integral from

[tex]\int (x^7)(x^4-1)^{1/3}[/tex]

Any help is good.

- #2

HallsofIvy

Science Advisor

Homework Helper

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- #3

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Ok right, exactly. And the new a and b would becomeA pretty obvious substitution to try is u= x^{4}- 1. Then du= 4x^{3}dx so you can separate that x^{7}into x^{4}x^{3}, use the "x^{3}with dx (andneverwrite an integral without the "dx") and then x^{4}= u+ 1.

[tex]\int x^7(x^4-1)dx= \int (u+1)u^{\frac{1}{3}}du= \int (u^{\frac{4}{3}}+ u^{\frac{1}{3}}*du[/tex]

- #4

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Thanks, I got it now!!1

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