Integration using exponentials

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Homework Statement



Screenshot2012-10-17at22915AM.png


the integral table says when you have the above form this will be the answer:

Screenshot2012-10-17at23832AM.png


Homework Equations





The Attempt at a Solution



I looked at the integral table here

http://integral-table.com/integral-table.html#SECTION00006000000000000000

and it says erf - I don't know what that means. In any case the erf x√a does not appear in the answer. I also don't understand the step

A√(λ/π) = A = √λ/π

I also don't see why there is no two in the denominator.
 
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g.lemaitre said:

Homework Statement



Screenshot2012-10-17at22915AM.png


the integral table says when you have the above form this will be the answer:

Screenshot2012-10-17at23832AM.png


Homework Equations





The Attempt at a Solution



I looked at the integral table here

http://integral-table.com/integral-table.html#SECTION00006000000000000000

and it says erf - I don't know what that means. In any case the erf x√a does not appear in the answer. I also don't understand the step

A√(λ/π) = A = √λ/π

I also don't see why there is no two in the denominator.

The definition of erf(x) IS include in the table.

RGV
 
Why is there no 2 in the denominator. I still don't know what erf means. I also don't understand the step

A√(λ/π) = A = √λ/π
 
g.lemaitre said:
Why is there no 2 in the denominator.
Because the integral is from -∞ to ∞, not from 0 to ∞.

g.lemaitre said:
I still don't know what erf means.
It means "error function". Don't worry about that.

g.lemaitre said:
I also don't understand the step

A√(λ/π) = A = √λ/π
You are not reading it correctly, that's why. What it reads is
A√(π/λ) = 1
therefore
A = √λ/π
 
ok, thanks for the help.
 
Prove $$\int\limits_0^{\sqrt2/4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx = \frac{\pi^2}{8}.$$ Let $$I = \int\limits_0^{\sqrt 2 / 4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx. \tag{1}$$ The representation integral of ##\arcsin## is $$\arcsin u = \int\limits_{0}^{1} \frac{\mathrm dt}{\sqrt{1-t^2}}, \qquad 0 \leqslant u \leqslant 1.$$ Plugging identity above into ##(1)## with ##u...

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