Integration within a DiffEQ problem

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    Diffeq Integration
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Homework Statement


Solve the given differential equation by using an appropriate substitution.



Homework Equations


(x^{2}+xy+3y^{2})dx-(x^{2}+2xy)dy=0
y=ux, dy=udx+xdu


The Attempt at a Solution


(x^{2}dx+ux^{2}dx+3u^{2}x^{2}dx)-(ux^{2}dx+x^{3}du+2u^{2}x^{2}dx+2ux^{3}du)=0
After combining, cancelling and moving terms into their appropriate places, I get:
\frac{dx}{x}=\frac{2u+1}{u^{2}+1}du


This is where I get stuck, I am unable to integrate the right hand side. Can anyone help me out a little?

Thanks.
 
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Split it into two parts. 2u/(u^2+1) looks easy by a substitution and 1/(u^2+1) looks like an arctan.
 
I cannot believe I didn't see that.

Thanks!
 
Prove $$\int\limits_0^{\sqrt2/4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx = \frac{\pi^2}{8}.$$ Let $$I = \int\limits_0^{\sqrt 2 / 4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx. \tag{1}$$ The representation integral of ##\arcsin## is $$\arcsin u = \int\limits_{0}^{1} \frac{\mathrm dt}{\sqrt{1-t^2}}, \qquad 0 \leqslant u \leqslant 1.$$ Plugging identity above into ##(1)## with ##u...
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