# Intensity and Power of isotropic sound

1. Jun 24, 2009

### turandorf

1. The problem statement, all variables and given/known data
An electronic point source emits sound isotropically at a frequency of 3000 Hz and a power of 34 watts. A small microphone has an area of 0.74 cm2 and is located 158 meters from the point source.
a) What is the sound intensity at the microphone ?

b) What is the power intercepted by the microphone?

2. Relevant equations
I=(power)/(area)
Avg power=(1/2)(mu)(v)(w^2)A^2 (not sure what all these mean)

3. The attempt at a solution
I tried Intensity=(power)/(area) but that was wrong. I had converted the area to m^2 too…any ideas?
1. The problem statement, all variables and given/known data

2. Relevant equations

3. The attempt at a solution

2. Jun 24, 2009

### LowlyPion

At 158 meters don't you have the surface of a sphere that has a radius of 158 meters?

Maybe if you know what % of this area that the area of the microphone represents on the sphere, you might get an idea of how much of the original 34 watts that's pushing the air around at the speaker is available for detecting?

http://hyperphysics.phy-astr.gsu.edu/hbase/acoustic/invsqs.html#c1