Interacting Fermion System Commutation

Xyius
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Problem Question
My question isn't an entire homework problem, but rather for a certain mathematical step in the problem which I assume to be very simple.

The problem is dealing with interacting fermion systems using second quantization formulas. I am essentially following my notes from class for this problem and the part I am stuck on is this.

<0,0|a_{2 \uparrow} a_{1 \uparrow}a_{1 \uparrow}^{\dagger}a_{2 \uparrow}^{\dagger}a_{1 \uparrow}a_{2 \uparrow}a_{1 \uparrow}^{\dagger}a_{2 \uparrow}^{\dagger}|0,0>=-1

My question is, why is this equal to -1?

Attempt at Solution
Here is my logic on how to evaluate this.

a_{1 \uparrow}^{\dagger}a_{2 \uparrow}^{\dagger}|0,0>=|\uparrow \uparrow>
then
a_{1 \uparrow}a_{2 \uparrow}|\uparrow \uparrow>=|0,0>
then
a_{1 \uparrow}^{\dagger}a_{2 \uparrow}^{\dagger}|0,0>=|\uparrow \uparrow>
finally
a_{2 \uparrow} a_{1 \uparrow}|\uparrow \uparrow>=|0,0>
Thus all together I get 1, not -1. Why is this equal to -1?
 
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Xyius said:
Here is my logic on how to evaluate this.

a_{1 \uparrow}^{\dagger}a_{2 \uparrow}^{\dagger}|0,0>=|\uparrow \uparrow>
then
a_{1 \uparrow}a_{2 \uparrow}|\uparrow \uparrow>=|0,0>
I believe the mistake is in the second equation above. There are sign conventions for Fermion operators operating on Fock states.

See equations 4, 5, and 6 here: http://www.phys.ufl.edu/~kevin/teaching/6646/03spring/2nd-quant.pdf
 
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