- #1

Shackleford

- 1,656

- 2

For (c), it looks like this set goes off to negative and positive infinity.

http://i111.photobucket.com/albums/n149/camarolt4z28/IMG_20110904_125145.jpg

For (e), I think this is right. Since r is in the rationals, r gets arbitrarily close to the square root of 5, so there are no particular numbers that are the min, max of the set. Also, since r is in the rationals, there is no particular number that is the sup or inf.

http://i111.photobucket.com/albums/n149/camarolt4z28/IMG_20110904_125117.jpg

For (f) and (g), the "limit" of the intersection and union appears to be the open interval (0,1). If that's the case, the answers should be the same. Since it is an open interval, 0 and 1 are not elements of the set, so there is no particular number that is the min, max. But, I could say 0 and 1 are the inf and sup, respectively. I'm not too sure about this.

http://i111.photobucket.com/albums/n149/camarolt4z28/IMG_20110904_125132.jpg

http://i111.photobucket.com/albums/n149/camarolt4z28/IMG_20110904_125145.jpg

For (e), I think this is right. Since r is in the rationals, r gets arbitrarily close to the square root of 5, so there are no particular numbers that are the min, max of the set. Also, since r is in the rationals, there is no particular number that is the sup or inf.

http://i111.photobucket.com/albums/n149/camarolt4z28/IMG_20110904_125117.jpg

For (f) and (g), the "limit" of the intersection and union appears to be the open interval (0,1). If that's the case, the answers should be the same. Since it is an open interval, 0 and 1 are not elements of the set, so there is no particular number that is the min, max. But, I could say 0 and 1 are the inf and sup, respectively. I'm not too sure about this.

http://i111.photobucket.com/albums/n149/camarolt4z28/IMG_20110904_125132.jpg

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