Internal Energy: gas inside piston

AI Thread Summary
The discussion centers on calculating the change in internal energy of a gas in a cylinder with a piston under specific conditions. The gas is initially at 300K and heated to 400K, with a heat capacity of 500J/K. The user calculates the heat added (Q) as 50,000 J using the formula Q = C * delta T. They also attempt to determine the internal pressure and the work done (W) by the piston, considering the weight and cross-sectional area. Ultimately, the user realizes they have solved the problem, indicating a successful conclusion to their calculations.
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A cylinder (cross section is 0.2m2) with a free moving piston is filled with gas. The piston is attached to a heavy weight W = 10000N. Outside the cylinder, the air is at 300K and 1atm. Initially the gas is at 300K, then it is heated to 400K. The heat capacity of the gas under the constant pressure is 500J/K.

If the length of the gas in the cylinder l increases by 20cm during the heating, find the change in the internal energy of the gas in Joule J.


Im thinking:

C = Q / delta T

C (delta T) = Q

500 x (400-300) = 50000 J = Q

so...delta U = Q - W

W = P delta V

i guess P is the pressure inside the piston...I've told something like this:

Inside pressure = outside pressure - weight_force/cross_sectional_area

I tried that, i came up with 456500 = ( 101300 - 10000) / .2

? i don't know...any help would be appreciated...:frown:
 

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oops, i actually got it...thanks though...
 
Since ##px^9+q## is the factor, then ##x^9=\frac{-q}{p}## will be one of the roots. Let ##f(x)=27x^{18}+bx^9+70##, then: $$27\left(\frac{-q}{p}\right)^2+b\left(\frac{-q}{p}\right)+70=0$$ $$b=27 \frac{q}{p}+70 \frac{p}{q}$$ $$b=\frac{27q^2+70p^2}{pq}$$ From this expression, it looks like there is no greatest value of ##b## because increasing the value of ##p## and ##q## will also increase the value of ##b##. How to find the greatest value of ##b##? Thanks
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