Intersection of A & B: Answer to Puzzling Question

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Set A has twice as many elements as Set B, with one-third of Set A's elements overlapping with Set B. The total number of unique elements in the union of Sets A and B is 42. Using the inclusion-exclusion principle, the correct calculation leads to the intersection being 12. The discussion highlights the importance of careful arithmetic in solving set theory problems.
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Homework Statement


Set A has twice the number of elements as Set B, 1/3 of the elements of Set A are the same as in Set B, the union of A and B is 42, what is the intersection?

The Attempt at a Solution



This was one of my exam questions, and I just want to see what the correct answer was. What I tried to do was
use the inclusion exclusion principle so

|AUB| = |A| + |B| - (1/3)*|A|
42 = |A| + 1/2|A| - (1/3)|A|
42 = (1/6)|A| + (3/6)*|A| - (2/6)*|A|
42 = (1/3)|A|

And 42 is the intersection, but that makes absolutely no sense, can anyone show me the correct way to get the answer?
 
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Draw a Venn diagram using Kn in each section (K different for each section). Answer of 12 falls out trivially.
 
Panphobia said:

Homework Statement


Set A has twice the number of elements as Set B, 1/3 of the elements of Set A are the same as in Set B, the union of A and B is 42, what is the intersection?

The Attempt at a Solution



This was one of my exam questions, and I just want to see what the correct answer was. What I tried to do was
use the inclusion exclusion principle so

|AUB| = |A| + |B| - (1/3)*|A|
42 = |A| + 1/2|A| - (1/3)|A|
42 = (1/6)|A| + (3/6)*|A| - (2/6)*|A|
42 = (1/3)|A|

And 42 is the intersection, but that makes absolutely no sense, can anyone show me the correct way to get the answer?
$$42 = |A \cup B| = |A| + |B| - |A \cap B| = 2|B| + |B| - (1/3)\underbrace{(2 |B|)}_{|A|} = (3 - 2/3) |B| = (7/3) |B|$$.
 
Panphobia said:

Homework Statement


Set A has twice the number of elements as Set B, 1/3 of the elements of Set A are the same as in Set B, the union of A and B is 42, what is the intersection?

The Attempt at a Solution



This was one of my exam questions, and I just want to see what the correct answer was. What I tried to do was
use the inclusion exclusion principle so

|AUB| = |A| + |B| - (1/3)*|A|
42 = |A| + 1/2|A| - (1/3)|A|
42 = (1/6)|A| + (3/6)*|A| - (2/6)*|A|
42 = (1/3)|A|

And 42 is the intersection, but that makes absolutely no sense, can anyone show me the correct way to get the answer?

I think if you had added 1+1/2-1/3 correctly you would have had it.
 
Wow elementary math mistakes everywhere haha, yea my mistake. I got it now.
 
I picked up this problem from the Schaum's series book titled "College Mathematics" by Ayres/Schmidt. It is a solved problem in the book. But what surprised me was that the solution to this problem was given in one line without any explanation. I could, therefore, not understand how the given one-line solution was reached. The one-line solution in the book says: The equation is ##x \cos{\omega} +y \sin{\omega} - 5 = 0##, ##\omega## being the parameter. From my side, the only thing I could...

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