Intervals and their subsets proof

hlin818
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Homework Statement


I reduced another problem to the following problem:

If I is an interval and A is a subset of I, then A is either an interval, a set of discreet points, a union of the two.

Homework Equations


The Attempt at a Solution



Is this trivial?
 
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It's false. For example, take the set (-1,1) and inside of it the set A of all rational numbers in between -1 and 1. Unless by union you mean any arbitrary amount of sets being unioned together, in which case it's a silly question because any set A is the union of the sets each containing a single point of A
 
Ah completely overlooked that, thanks. I'll post up the full problem because now I'm sort of stuck.
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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