Intro to the Ionization Energy of Atomic Hydrogen

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SUMMARY

The discussion focuses on the ionization energy of atomic hydrogen, utilizing the formula for electron energy based on the primary quantum number n: $$ E_{n}=\mu c^2\sqrt{1-\frac{Z^2\alpha^2}{n^2}} $$, where Z=1 for hydrogen. The reduced mass (μ) is calculated using the formula $$\mu = \frac{m_e\times m_{n}}{m_e+m_{n}} $$, which is essential for accurate ionization energy calculations. Participants noted the limitations of Wolfram Alpha in displaying significant figures and suggested improvements for the article's clarity and completeness.

PREREQUISITES
  • Understanding of quantum mechanics, specifically the concept of quantum numbers.
  • Familiarity with the fine structure constant (α) and its significance in atomic physics.
  • Knowledge of reduced mass calculations in atomic systems.
  • Basic proficiency in using computational tools like Wolfram Alpha for scientific calculations.
NEXT STEPS
  • Research the implications of the fine structure constant (α) in atomic energy levels.
  • Explore advanced calculations of ionization energy for multi-electron atoms.
  • Learn about the limitations of computational tools like Wolfram Alpha in scientific calculations.
  • Investigate the role of significant figures in scientific reporting and calculations.
USEFUL FOR

Students and professionals in physics, particularly those studying atomic structure and quantum mechanics, as well as educators looking to enhance their understanding of ionization energy calculations.

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Introduction
In previous articles relating to various transition energies in Hydrogen, Helium, and Deuterium we have employed the following formula for electron energy given a particular primary quantum number n:
$$ E_{n}=\mu c^2\sqrt{1-\frac{Z^2\alpha^2}{n^2}} $$
where ## \alpha ## is the fine structure constant and ## \mu ## the reduced electron mass for a single electron bound to whichever nucleus. Z=1 for Hydrogen and Deuterium, Z=2 for Helium. Reduced mass is calculated from electron mass and nuclear mass as follows: $$\mu = \frac{m_e\times m_{n}}{m_e+m_{n}} $$.
Calculation of Ionization Energy: Atomic Hydrogen
Perhaps one of the simplest applications of this formula is the determination of the ionization...

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as many significant figures as Wolfram Alpha is prepared to calculate!
Unless you click on "more digits".

The WolframAlpha image has a low resolution in the article and you could have added a link to WA with the calculation filled in.
 
Many thanks - the article wasn't actually finished and I accidentally pressed submit. Anyway I'll chat to Greg and either temporarily 'withdraw' it or just do some online editing. It's very 'junky' as it stands - not even any references.

Re "more digits": I'm not sure if this option is available when you are using scientific constants as in this calculation. WA seems to put some kind of limit on the number of significant figures it will display.
 
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