Introduction to energy problem - did I do this right?

AI Thread Summary
The discussion centers on a physics problem involving a bullet penetrating wood, where the average opposing force is 50,000N. The user attempts to apply energy conservation principles, concluding that the bullet penetrates 0.03 meters. However, a response points out that while the methodology appears correct, the problem itself is flawed because average force does not directly allow for the calculation of distance without knowing the time involved. The distinction between average force and the assumption of constant force is emphasized, highlighting a common misconception in energy problems. Understanding these nuances is crucial for solving similar physics problems accurately.
JSmithDawg
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Homework Statement


The bullet strikes a block of wood which exerts, on average, a force of 50,000N opposing the motion of the bullet. How far does the bullet penetrate?

Mass of bullet = 25g
Initial velocity of bullet = 350 m/s
Final velocity of bullet = 0 m/s

Homework Equations


Ei+work=Ef
K = ½mv^2
Energy = Force * Displacement

The Attempt at a Solution


Please excuse my attempt of it's egregiously wrong, I was just introduced to energy yesterday; this is one of the first problems I'm doing.

Anyways, because the final velocity of the bullet is zero, the bullet must have lost all of its energy, making Ef=0 J. The bullet initially had kinetic energy, making Ei=K. Thus, my new equation is
K+work = 0 J
½mv^2+work=0 J

I also know that the problem gave me how many Newtons oppose the object, but I need to find out how much energy it used. Since Energy = Force*Displacement, I can rewrite the equation as:
½mv^2+(F*Δx) = 0 J
So I solved it below...
½(.025kg)(350 m/s)^2+(-50000N*Δx) = 0 J
Δx=.03m

Did I do this problem right? If not, what did I do wrong?
 
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I didn't check your arithmetic, but you methodology is correct.

Chet
 
It's the right answer according to what the questioner seems to expect you to do, but the question is actually wrong.
Knowing the average force you cannot deduce the distance, only the time. Your method effectively assumes a constant force. Average force is defined as ##\Delta##momentum/##\Delta##time. In general, this gives a different number from ##\Delta##KE/displacement.
 
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