Introductory Analysis: Inductively define a sequence Sn

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Homework Statement




Let S1=1 and inductively define the sequence Sn so that Sn+1 = \sqrt{Sn + 1}


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The Attempt at a Solution



I'm not sure what it means to "inductively define".

I think it wants me to come up with an equation for Sn by using Sn+1.

Does it want me to define Sn in terms of Sn+1 or just in terms of n?

How should I go about starting this?
 
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Surely this isn't the complete assignment . Please post the entire question only then I can help you.
 
Let S1=1 and inductively define the sequence (Sn) so that Sn+1 = \sqrt{Sn + 1} for n\in Natural Numbers.

(a) Prove that Sn is a monotonically increasing sequence.
(b) Prove that Sn is a bounded sequence.
(c) Prove that Sn converges.
(d) Prove that lim(Sn)=\frac{1}{2} (1 + \sqrt{5} )
 
I'm sorry. That's the whole thing now.

I didn't realize that you needed the a,b,c,d parts to do the first part, I thought you had to inductively define Sn and then, using that definition, do the rest.
 
'Inductively define' doesn't mean you have to do anything. It's just pointing out that S_{n+1}=sqrt(S_n+1) is already an 'inductive' definition.
 
Oh, haha. Thank you.
 
Prove $$\int\limits_0^{\sqrt2/4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx = \frac{\pi^2}{8}.$$ Let $$I = \int\limits_0^{\sqrt 2 / 4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx. \tag{1}$$ The representation integral of ##\arcsin## is $$\arcsin u = \int\limits_{0}^{1} \frac{\mathrm dt}{\sqrt{1-t^2}}, \qquad 0 \leqslant u \leqslant 1.$$ Plugging identity above into ##(1)## with ##u...

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