Invariance of quadratic form for unitary matrices

spaghetti3451
Messages
1,311
Reaction score
31

Homework Statement



Show that all ##n \times n## unitary matrices ##U## leave invariant the quadratic form ##|x_{1}|^{2} + |x_{2}|^{2} + \cdots + |x_{n}|^{2}##, that is, that if ##x'=Ux##, then ##|x'|^{2}=|x|^{2}##.

Homework Equations



The Attempt at a Solution



##|x'|^{2} = (x')^{\dagger}(x') = (Ux)^{\dagger}(Ux) = x^{\dagger}U^{\dagger}Ux = x^{\dagger}x = x^{2}##.

Am I correct?
 
Physics news on Phys.org
failexam said:
Am I correct?
Yes. (Although I always need to get used to the physicist's notation for the Hermitian transpose. :wink:)
 
Thanks!

I always wish I could see from the mathematician's point of view, being as I am from a Physics background. :smile:
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
Back
Top