Inverse Function Homework: Slope of 1/2

jordan123
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Homework Statement


Hello, this is what the question states:

Consider the function f(x) = 2x + cos(x). Find all points at which the inverse function has a slpe of 1/2.


The Attempt at a Solution


What I did was find where the original function has a slope of 2. Those x values would become the y values for the inverse function. So x would = 0, pi, 2pi.

Is this correct? Enlighten !
 
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That seems right. You have three points. But there are many more, right? Like 3pi, 4pi, -pi, -2pi, etc? The problem did say to find ALL points.
 
Ok, thanks. And you so it would be like n pi.
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...

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