# Inverse Laplace

1. Homework Statement
Inverse laplace transforms

F(s)=$$\frac{5s-2}{s^{2}(s-1)(s+2)}$$

2. Homework Equations
Residue technique

3. The Attempt at a Solution

F(s)=$$\frac{5s-2}{s^{2}(s-1)(s+2)} = \frac{k1}{s^{2}} + \frac{k2}{s-1} + \frac{k3}{s+2}$$

I solved for K1,K2, and K3, which all came to be 1.

answer=$$e^{t}+e^{-2t}+t$$
textbook answer = $$e^{t}+e^{-2t}+t -2$$

Can someone explain to me how did the -2 come?

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