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I'm struggling to solve the following integral
∫ x/(√27-6x-x2)
my attempt is as follows:
∫x/(√36 - (x+3)2)
= ∫1/ √(36 - (x+3)2) + ∫x+1/ √(36 - (x+3)2)
= arcsin (x + 3)/6 + this is where I got stuck.
∫ x/(√27-6x-x2)
my attempt is as follows:
∫x/(√36 - (x+3)2)
= ∫1/ √(36 - (x+3)2) + ∫x+1/ √(36 - (x+3)2)
= arcsin (x + 3)/6 + this is where I got stuck.