Investigating the convergence of a sequence

Elysian
Messages
33
Reaction score
0

Homework Statement



Study the convergence of the following sequences

a_{n} = \int^{1}_{0} \frac{x^{n}}{1+x^{2}}

b_{n} = \int^{B}_{A} sin(nx)f(x) dx



The Attempt at a Solution



For the first one, I said it was convergent. I'm not exactly sure why though, my reasoning was something like this

for all values n>0, the sequence is increasing. It seems to be bounded by 1/2? (not sure here, the integral is messing me up)an increasing sequence that is bounded is also convergent.

The second one, I'm not even sure where to start. Maybe an integration by parts which would end up to repeat itself, as that's what I think I see.
 
Physics news on Phys.org
For a_n, notice that
0 \leq \frac{x^n}{1 + x^2} \leq x^n
for all 0 \leq x \leq 1.

For b_n, are there any constraints on f(x)?
 
for bn:
step1:take f(x) to be any constant an show that the limit is 0.
step2:take f(x) to be any piecewise constant on [A,B] and use step1 to show that the limit is again 0.
step3:take f(x) to be any Riemann integrable function on [A,B],use the definition of the Riemann integral for the existence of a sequence of piecewise constant functions gn(x) such that the integral of f(x)-gn(x) tends to 0,and prove (using the preceding step,the triangle inequality and bound for sin ) that the limit of bn is 0.
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...

Similar threads

Back
Top