involving force and Newtons laws

AI Thread Summary
A physics problem involves a 100 kg fireman being lowered by a rope with a breaking strength of 800 N from a height of 10 meters. The participant is unsure how to calculate the fireman's velocity upon reaching the ground and the average normal force during his stopping distance of 20 cm. Key points include determining the net force acting on the fireman, which is 200 N downward, leading to an acceleration of 2 m/s². The discussion emphasizes using energy conservation principles to relate potential energy to kinetic energy, factoring in the work done by the rope. Participants provide guidance on calculating acceleration and velocity, suggesting that understanding these concepts will help solve the problem.
Cicima
Messages
20
Reaction score
0
I got this problem as part of a long homework packet, was able to figure out all the problems but the last 3, so here is one of them, but i don't have a book. I really have no idea on how to approach this problem, so i was hoping someone could lead me through it and help me figure it out...

A 100 kg fireman is being lowered from a floor 10 meters above the ground by a rope whose breaking strength is 800 N. The fireman starts from rest and the person loewring the fireman knows that the 800 N limit must be adhered.
Draw a free body diagram showing all of the forces extered on the fireman.
What is the fireman velocity when he touches the ground?
The fireman moves 20 cm during his stopping. What is the average normal force exerted on the fireman during the stop?
I don't really know where to start, not sure of the equation i need to find the fireman velocity and how to use the given numbers. As forthe diagram, i drew one showing 100kg of his wieght pushing down, the ropes strength which is 800N while he's getting lowered. So what now? Please help me through this problem, i don't have a book and have looked online for formulas and similar problems but can't find any.
 
Physics news on Phys.org
Can someone please help me do this problem?

So far i got...
the fireman is accelerating such that ma=mg-800N
i think i have to find a, but i don't know how to, can you guys help me find it?
after i find a, i can find v by doing d=v^2(2a) where D is 10m, but i don't know how to find a so that's olding be back.
after i find v, the aveerage force of impact is mv^2/2=F*d, where d=20cm
So i guess my questions are how do i find acceleration and am i right with what my other work is? I am hoping someone can help so i can finally finish this and get some sleep. :zzz:
 
Cicima said:
I got this problem as part of a long homework packet, was able to figure out all the problems but the last 3, so here is one of them, but i don't have a book. I really have no idea on how to approach this problem, so i was hoping someone could lead me through it and help me figure it out...

I don't really know where to start, not sure of the equation i need to find the fireman velocity and how to use the given numbers. As forthe diagram, i drew one showing 100kg of his wieght pushing down, the ropes strength which is 800N while he's getting lowered. So what now? Please help me through this problem, i don't have a book and have looked online for formulas and similar problems but can't find any.
100kg weight is about 1000N (Weight=mg, I used g =10 because I'm tired too.) 1000 down, and 800 up is the max, that's a net of 200 down, right? F_net=ma, per Newton2. 200 = 100a. a=2. Examine the forces and write the right equation. Now let's get some zzzz's...
 
It looks like you are able to use energy methods, that's probably all you need to solve this problem.

If the fireman were in free fall, then all of the potential energy would be converted to kinetic energy, by the conservation law, so that

K_final - U_Start = 0

However, there is an external force here, which is the rope. The rope is doing work, it is actually bleeding energy out of the system that would have gone into kinetic energy. So the system is losing energy. So...

K_final - U_Start = ?

If you can figure that out, then you can solve for the velocity.

Speaking of sleep.. What a good idea. Hope this is enough to help you solve it now.

Good night,
Dorothy
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top