Ionic equations and Spectator Ions question REALLY SHORT

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The discussion revolves around balancing the ionic equation for the reaction between lead(II) nitrate and sulfuric acid. The initial equation presented was Pb(NO3)2(aq) + H2SO4(aq) → PbSO3(s) + HNO3(aq), which was later corrected to Pb(NO3)2(aq) + H2SO4(aq) → PbSO4(s) + 2HNO3(aq). Participants debated whether to eliminate H2 and H+ ions during the balancing process, with some confusion about the correct products formed. The consensus suggests that H2SO4 releases H+ ions, and balancing should be done at the end. The final balanced equation is confirmed as Pb(NO3)2(aq) + H2SO4(aq) → PbSO4(s) + 2HNO3(aq).
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Homework Statement


Pb(NO3)2(aq) + H2SO4(aq) → PbSO3(s) + HNO3(aq)
Pb + (NO3)2(aq) + H2 + SO4(aq) → PbSO3(s) + H + NO3(aq)

The Attempt at a Solution



So far I've done that, and now I'm stuck I see h2 and h can I cross out both or do i have to balance right now? My teacher said you can balance at the end. Can i cross out one h on the left and the remaining on the right?
 
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H2 is a gas. H2SO4 (aq) only releases H+ ions.
 
can i get rid of them or no?
 
Last edited:
Could Snazzy be saying you won't get HNO3? rather H + NO3 ?
 
no i copied exactly the way it is from my prentice hall chem book hwork assignment
 
wait there is a problem
Pb(NO3)2(aq) + H2SO4(aq) → PbSO4(s) + HNO3(aq)
Pb + (NO3)2(aq) + H2 + SO4(aq) → Pb + SO4(s) + H + NO3(aq)
 
To balance I think you get
Pb(NO3)2(aq) + H2SO4(aq) --> PbSO4(s) + 2HNO3(aq)

if that helps any.
 
ok
thanks
 
I know, not much help. Sorry :(
 
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