Ionic equations and Spectator Ions question REALLY SHORT

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Discussion Overview

The discussion revolves around balancing ionic equations, specifically the reaction between lead(II) nitrate and sulfuric acid. Participants explore the treatment of spectator ions and the balancing process within the context of a homework problem.

Discussion Character

  • Homework-related

Main Points Raised

  • One participant presents a reaction equation and expresses confusion about whether to balance before or after canceling out ions.
  • Another participant clarifies that H2 is a gas and that H2SO4 releases H+ ions, implying a distinction in how to treat these species in the equation.
  • There is a question about whether HNO3 should be represented as H + NO3, indicating uncertainty about the correct formulation.
  • A participant identifies a potential error in the initial equation provided, suggesting a correction to the products of the reaction.
  • Another participant proposes a balanced equation, indicating a possible solution to the balancing issue raised earlier.
  • One participant acknowledges the limited help provided in the discussion.

Areas of Agreement / Disagreement

Participants express varying levels of understanding regarding the balancing of the equation and the treatment of ions, with no consensus reached on the correct approach or final balanced equation.

Contextual Notes

There are unresolved issues regarding the treatment of spectator ions and the balancing of the equation, as well as potential discrepancies in the reaction products.

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Homework Statement


Pb(NO3)2(aq) + H2SO4(aq) → PbSO3(s) + HNO3(aq)
Pb + (NO3)2(aq) + H2 + SO4(aq) → PbSO3(s) + H + NO3(aq)

The Attempt at a Solution



So far I've done that, and now I'm stuck I see h2 and h can I cross out both or do i have to balance right now? My teacher said you can balance at the end. Can i cross out one h on the left and the remaining on the right?
 
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H2 is a gas. H2SO4 (aq) only releases H+ ions.
 
can i get rid of them or no?
 
Last edited:
Could Snazzy be saying you won't get HNO3? rather H + NO3 ?
 
no i copied exactly the way it is from my prentice hall chem book hwork assignment
 
wait there is a problem
Pb(NO3)2(aq) + H2SO4(aq) → PbSO4(s) + HNO3(aq)
Pb + (NO3)2(aq) + H2 + SO4(aq) → Pb + SO4(s) + H + NO3(aq)
 
To balance I think you get
Pb(NO3)2(aq) + H2SO4(aq) --> PbSO4(s) + 2HNO3(aq)

if that helps any.
 
ok
thanks
 
I know, not much help. Sorry :(
 

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