Andre
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Objectively, it seems simple, compare the statements and quantifications in "The Inconvenient Truth" with the suppositions of the IPCC in that period.
mheslep said:Yes I see that you may or may not be speaking tongue-in-cheek there,
To what end? After making the first statement to 'Bob in the street', do researchers expect to come back later and say 'just kidding then, I was being condescending for your own good, but now I really know, trust me this time, I'm a scientist?'
russ_watters said:Minor quibble with your method, vanesch: We are changing the injection of CO2 into the atmosphere. It's gone way, way up. So I think that regardless of what we do over the next 50 years, we'll get our answer. Maybe the global temperatures will keep going up and maybe they won't.
Fair enough, good for you then.vanesch said:Just for the sake of the knowledge and the fun of doing experiments. We will have performed the experiment, and we will have seen. That's what science is about, no ?
Art said:Thanks Vanesch, I've queried this with the author of the article if he responds I'll post his reply.
me said:Hello!
I've read with some interest your contribution on:
http://www.middlebury.net/op-ed/global-warming-01.html
Now, you raise interesting points, but there seems to me to be one big elementary fallacy in the main argument you bring forward:
"But the entire atmosphere isn't composed of CO2. In fact the current concentration in the atmosphere is only about 380 parts per million. It's what we call a "trace gas". So how much heat can our trace amounts of CO2 actually absorb? The math is simple: 8% ( or .08 ) x 380 PPM ( .000380 ) = .0000304, or about thirty millionths of the radiated heat."
This calculation seems to be unfounded. Absorption has nothing to do with relative composition, but with the cross section times the surface density of absorbing particles. Whether or not you ADD other stuff to it.
Let us assume that, say, 1 bar of CO2 over, say, 5 meters absorbs 8% of the spectrum, just by "being black" in a certain spectral region, and that this region represents 8% of the entire spectral energy content. Fine.
Now, SPREAD this 1 bar of CO2, 5 meter thick, over a column of 20 km. We now have of the order of 0.25 mbar of CO2. Guess what ? The absorption in your 20 km of 0.25 mbar of CO2 is identical to the absorption of your 5m CO2 of 1 bar. So we still pick out 8% of the spectrum, right ?
Now, add 1 bar of nitrogen/oxygen to it. What happens ? In as much as nitrogen and oxygen can be considered transparent, NOTHING changes. There is still the same number of CO2 molecules in a column of 1 square cm. We still pick out 8%.
So I don't see how you can include the RATIO of CO2 to N2/O2 or whatever in the calculation of your maximum "blackness" of CO2...
Once you have enough molecules per cm^2 to "be black", no ADDING other stuff is going to make it more transparent.
cheers,
Patrick Van Esch.
me said:Hello again,
I think you don't understand my objection. I can live with the square
profile, and the 8% for a "black" atmosphere. What I object to, is that
you multiply this with the ratio of CO2 molecules over O2/N2 molecules.
That simply makes no sense. What counts is the amount of CO2 in the
column, not whether there is ALSO N2 or O2. And as such, you arrive at a
ridiculously low absorption (one in a million) which is entirely not
justified.
Remove all the N2/O2, while you keep the 0.3 mbar or so of CO2, and,
according to your technique, you would obtain 8% (because the ratio is 1
now). Well, the real absorption is going to be the same.
Add 1000 bar of N2, and you would, according to your estimation, even have
1000 times less absorption. That is simply not correct.
So there is no justification at all to multiply the 8% with 0.0003...
cheers,
Patrick.
him said:If you add N2 and O2 to the mix, you do change the collision cross sections, because the CO2 is more "spread out" and becomes a smaller "target".
===> I'm pretty acquainted with radiation transport problems, but more in
the nuclear world. For instance, typical problems I look into is the
transport problem of neutrons generated in a radioactive source, and which
propagate through a scattering/absorbing medium.
The issue we look into here is similar (although I can understand that
some details differ), and I know that general radiation problems can be a
pain.
However, you will not convince me that a homogeneous mixture of two
substances, one of which acts as an observer, will become more transparant
as JUST the amount of absorber, in the ratio of the two substances. In
fact, all extra scattering by the second material will actually INCREASE
the overall absorption, simply because the total path length of the
radiation has become longer than the direct "exit" path from source to
escape boundary.
If you want to go for a simple estimation, you simply estimate the
absorption along a straight line by only the absorbing medium (here, CO2).
Extra elastic scattering will only increase that absorption.
I'm not nitpicking you know. I try to point out a totally absurd
calculation.
Even in your ideal lab experiment: take 10 meters of CO2 at 1 bar, and
look at the absorption. Now ADD 10 bars of N2 to your CO2 container
(while keeping the 1 bar of CO2, so total pressure 11 bars). Are you
seriously going to claim that you will absorb 10 times LESS of the IR beam
you sent in ?
The cross section for a molecule to absorb a photon is independent of the
concentration of the gas.
The probability of absorption in a column of gas is the amount of
molecules per square cm in that column, times the cross section.
cheers,
Patrick.
Gokul43201 said:vanesch,
Is this person saying that the total absorption cross section is different for a fixed number of molecules "X", for different levels of dilution (and that the cross section scales with the concentration of X) ?
I haven't read the original article.
Hi again,
I saw that you modified the page :-)
However, I still don't buy the argument. You see, when you write:
===
So, let's use our imagination and tack up a million one-inch bottle caps on the side of a really big building, with them all spaced 3.3 inches apart, and with only 380 of them being red and the rest all blue. If they're evenly mixed up ( like the wind mixes the atmosphere ) then the red bottle caps (representing CO2) now are going to be spaced 8,684 inches, or 723 feet apart. Now you know why we call CO2 a "trace gas" in the atmosphere.
===
there's no objection to this, but now consider that there is ONLY this trace gas, at 0.38 mbar. Then the red caps are ALSO 723 feet apart, and we already know that this absorps ALL of the 8% (remember, the 10 meters of CO2). So in how much is ADDING the blue caps going to DIMINISH the absorption by the red caps ?
You see, it is not as if initially, you had them 3 inches apart, and you absorbed 8%. You ALWAYS had them 723 feet apart (the density of CO2 molecules per square centimeter of atmosphere column). No ADDING of blue caps is going to let the radiation get out easier.
===
Some of the sharper physics students out there are probably asking themselves, "Hey what about scattering?" If your physics professor ever gave you the question, "Why is the sky blue?", then you're familiar with Raleigh scattering theory and you've probably already done the math and learned that in the temperature ranges we're dealing with here, the scattering is so small as to be negligible.
===
Granted. So the N2/O2 doesn't play a role. So the blue caps are in fact infinitesimally small, compared to the red caps. In what way does adding infinitesimally small blue caps to a certain density of red caps diminish the probability to hit a red cap ?
===
Now, to finish this problem, we need to estimate a "capture cross section" - the probability that a particular CO2 molecule mixed in with everything else in the air will ever encounter one of the highly specific IR photons in the absorption spectrum. We'll assume the mixing is homogeneous, and set the geometry for capture based on the known percentage of CO2 in the air, which is 380 PPM. So based on this highly simplified picture, how much heat can our trace amounts of CO2 actually absorb? The math is simple: 8% ( or .08 ) x 380 PPM ( .000380 ) = .0000304, or about thirty millionths of the radiated heat.
===
You are STILL making the same error! The RATIO of CO2 to N2/O2 has nothing to do here.
The confusion can be of several types. The most evident one is that you seem to think that you have red caps (CO2), and blue caps (N2/O2) "of the same size" (same cross section, which isn't true but that doesn't matter), and IF WE HIT A BLUE ONE, WE WON'T HIT A RED ONE. But that's not true ! If you hit a blue one, this doesn't change your probability of hitting a red one! It would indeed be a correct reasoning if N2/O2 were just as absorbing as CO2. Then you are right. Then the probability of being absorbed by CO2 INSTEAD OF being absorbed by N2/O2 would depend on their ratio. In other words, the O2/N2 are IN COMPETITION with the CO2, and have similar cross sections. But we take the hypothesis here that N2/O2 doesn't absorb (in the same band) as CO2, and, at most, scatters (leaving the photon intact to be again absorbed by CO2). But then, you even make the hypothesis that this N2/O2 scattering is neglegible.
The other possible confusion is that you seem to think that there is a linear relationship between the amount of radiation absorbed in different situations, and the ratio of absorbant in both. This is not true, because it is an exponential relationship (Beer's law). So the error might be: if a FULL atmosphere of 1 bar of CO2 can absorp 8% (spectral selection), then an atmosphere of only 0.38 mbar of CO2 can only absorb proportionally: 8% x 0.000038.
But that is not true. If you have a light source which emits red light and blue light, and you put 500 pieces of red glass behind it, then only the red light gets true, so, say, 50%. But that doesn't mean that if you put only one piece of red glass behind it, that you will only absorb 0.1% of the light, and let 49.9% of the blue light get past it! One piece of red light already absorbs all of the blue light, hence 50%. If you add 499 extra pieces, this won't change a thing.
What is absorbed is given by 1 - exp(- d rho sigma) where d is the thickness, rho the particle density per volume element, and sigma the microscopic cross section. d times rho gives you the number of particles in the column. Now, if d rho sigma is, say, 20000, then you absorb everything, and if you now divide d rho sigma by 20, you STILL absorb about everything, not 20 times less.
cheers,
Patrick.
me said:===> In what way does ADDING molecules INCREASE the space of others ??
You see, the thing I'm disputing is that you seem to make a difference in total absorption between:
a) an atmosphere consisting solely of 0.35 mbar of CO2 (which, I presume, you accept that it can potentially absorb 8% of the BB spectrum, because 0.35 mbar of CO2, over several km, comes down to 1 bar of CO2 over a few meters in surface density)
b) an atmosphere consisting of 0.35 mbar of CO2 (partial pressure) PLUS 1 bar of N2/O2.
I can assure you that the average distance between CO2 molecules in BOTH cases is the same.
So now you need to explain me how it comes that ADDING 1 bar of N2/O2 to a 0.35 mbar CO2 atmosphere is going to DECREASE the absorption of the CO2, and is going to INCREASE the distance between individual CO2 molecules...
me said:I'm not discussing climate change or anything, I'm trying to point out an elementary but gross error in a single step, which is the deduction that the maximum BB energy absorption can at most be 8% times the CO2/N2-O2 ratio. This step is wrong *in principle*.
The reason is that if it were true (but it isn't) then indeed, the discussion stops there, and anyone going further is indeed a total ignoramus of elementary physics. This is what you present on your page. But unfortunately, it is not correct *in principle*. No matter whether or not there is climate change, whether or not in the end CO2 plays a role or whatever. The *reasoning* is faulty.
The simple statement that a pure CO2 atmosphere (of what thickness and pressure ?) would absorb 8%, and the fact that in the real atmosphere there is about 3000 more N2-O2 added to it, DOESN'T IMPLY that the atmosphere can at most absorb 8% / 3000.
Again, this is simply demonstrated by your lab experiment: take 10 meters of 1 bar of CO2, and a beam of IR radiation. You find that you absorb 8% of the spectrum totally. Now ADD 10 bars of N2 to your gas. Do you really expect now that you only absorb 0.8 % of the spectrum ? Of course not. You will STILL absorb 8%.
From that point on, any further argument made is put in doubt too (in the same way as the erroneous arguments in Gore's movie put everything else in doubt). It is like in an interview for a job: once you've found ONE erroneous statement by the candidate about his CV, you don't believe a word anymore for any other argumentation he might devellop.
Cheers,
Patrick.
Well, I see one big blunder already:
ecofan said:It's reasonably valid to use partial pressure arguments to estimate "collision cross sections", since the radiation is diminishing per the inverse square law and the target molecules are thinning at an even faster rate. Lab science and the real world aren't always in agreement, and the real atmosphere simply can't be replicated in the lab. Straightforward linear absorption just doesn't apply to the atmospheric geometry.
http://www.middlebury.net/op-ed/global-warming-01.html"
This fellow is writing for the layman, not the geek. His approximations are rough... some are generous, some are thin. It tends to balance out. It's a pretty good conclusion, at any rate, and better than anything else I've seen written so the ordinary non-scientist can understand.
Really! Did you get past this paragraph (quoted below), or like me, gag at the nonsense and give up?ecofan said:This fellow is writing for the layman, not the geek. His approximations are rough... some are generous, some are thin. It tends to balance out. It's a pretty good conclusion, at any rate, and better than anything else I've seen written so the ordinary non-scientist can understand.
blogger said:Atoms and molecules are very tiny things, and the distances between them are therefore also very small. Physicists like to use a unit of measure called an Angstrom, which is a nano-meter, or a billionth of a meter. A molecule like CO2 has a size of around 2 Angstroms, and in an "Ideal Gas", the spacing is about 3.3 Angstroms apart. The so-called Ideal Gas is one in which 10 to the 24th power number of molecules occupies a space of about 22 liters, at a pressure of 760mm of mercury and 273 degrees Kelvin - called the "standard temperature and pressure".
Oh boy! For any given temperature and pressure, you can calculate the intermolecular spacing of gas molecules on the back of a very small envelope, and you'll see that the quoted number is off by an order of magnitude. You don't need to look up any references for it!ecofan said:I wrote your objections to the guy and got an almost immediate reply, thanking me for pointing out the error. He also says he's using the published intermolecular spacing for N2 as a substitute for CO2, and if we have a better reference, he'd be pleased to know about it.
Is this something that really needs deep investigation? The lattice parameter of diamond is about 3.5 angstroms. Does this person really need to be given a reference to be shown that the intermolecular of a gas at STP should not be comparable to that of a solid with similar atomic make-up?If it turns out to be 33 angstroms instead of 3.3, he'll likely correct it, as it appears he has already done with the tenth-off nanometer thing.
No, it is not. It is defined by how the molar volume scales with temperature and pressure.And even I know that an ideal gas is also defined by molar volume and stp - so what's the rub there?
Not I. Are you a worshipper of crackpottery?Are you guys a bunch of Al Gore worshipers?
The day I start growing a fondness for flies, I'll be sure to use that advice.You catch more flies with honey than with vinegar.
Congratulations on presenting a quintessential example of an ad-hominem attackGokul43201 said:Really! Did you get past this paragraph (quoted below), or like me, gag at the nonsense and give up?
In that one paragraph, the author has produced more high school level errors than I've seen in any single paragraph by any high schooler.
1. Atoms and molecules are small. Therefore, distances between them are small? Hello? I'm currently sitting near a chamber where molecules are several inches apart.
2. 1 Angstrom = 1nm? Really? I recommend the first chapter or inside cover of any high school physics text.
3. Intermolecular spacing at STP is about 33 Angstroms, not 3.3 Angstroms. But I can see how you'd make that mistake if you don't know your Angstroms from your nanometers!
4. The definition of a mole of a gas is independent of whether or not it is ideal. The author thinks he's providing a definition of an ideal gas, while he is simply defining a mole, and in no way whatsoever, describing a "so-called Ideal Gas."
I sure hope this person does not have a degree in the physical sciences - that would be embarrassing!
Ad hominem? Pointing out gross mathematical/scientific errors is an ad hominem attack?Art said:Congratulations on presenting a quintessential example of an ad-hominem attack![]()
Was that really the only typo in my post? I'm surprised!btw high schooler should be high schooler or high-schooler. So based on your logic and your error it follows everything you have ever done or written is wrong.
I looked again, and I see now that he's also removed the entire paragraph about the short extinction length for atmospheric CO2 (quoted by vanesch in post #20) which essentially is all you need to see to realize that his rationale for multiplying by 380ppm is flawed. Without this paragraph, it is now still conceivable that dilution could result in a reduction of absorption if the extinction length is much greater than the thickness of the atmosphere. But this is not the case, as he had himself pointed out before ... but new readers will no longer be able to tell, because he's removed the very statements that debunk the rest of his argument.ecofan said:Looks like he's bought your 33 angstrom argument.
Gokul43201 said:I looked again, and I see now that he's also removed the entire paragraph about the short extinction length for atmospheric CO2 (quoted by vanesch in post #20) which essentially is all you need to see to realize that his rationale for multiplying by 380ppm is flawed. Without this paragraph, it is now still conceivable that dilution could result in a reduction of absorption if the extinction length is much greater than the thickness of the atmosphere. But this is not the case, as he had himself pointed out before ... but new readers will no longer be able to tell, because he's removed the very statements that debunk the rest of his argument.
ecofan said:And if the comment "the CO2 in the atmosphere ALREADY absorbs ALL of the IR radiation in the band, so adding more to it won't change anything" from PF Mentor is correct, then we can all go out and buy a SUV without having any guilt.
I haven't read the content at that url vanesch, but I think the scientific community is pretty coherent about one thing - the absorption increases logarithmically with CO2 concentration in the vicinity of present day concentrations. In the absence of any positive feedback mechanism (coming from other places than just the atmospheric composition), it would take exponential increases in CO2 concentration to produce the similar increases in warming.vanesch said:The funny thing is that another claim that CO2 increase will almost not affect any greenhouse effect, is to be found here:
http://www.john-daly.com/artifact.htm
is based on exactly the opposite conclusion: the CO2 in the atmosphere ALREADY absorbs ALL of the IR radiation in the band, so adding more to it won't change anything.
Now, I have to say that I don't find any gross error in principle here (assuming the numbers cited are correct).
Wow! That completely unnecessary and totally misleading description is positively embarrassing!blogger said:Side note: Both Oxygen and Nitrogen don't like to live alone. They prefer to find another and stick together into a diatomic ( 2 atom ) molecule. Thus the molecular weight of atmospheric oxygen or nitrogen is approximately twice that of one of them alone. We say "approximately", because it takes energy to bind them together, and mass and energy are equivalent stuff, as our good friend Dr. Einstein explained with his famous equation E=MC2.
And that's a joke!Now, you can sit back and give yourself a pat on the back, because you now know more pure physics of the atmosphere than a lot of so-called "climate scientists", and likely know more than almost all of the non-scientist Popular Journalists and other writers churning out panic-stricken books and newspaper articles on the subject.
Gokul43201 said:All these naive "first principle" calculations are really trying to reinvent the wheel, in an age where we already have self-lubricating bearings.
Side note: Both Oxygen and Nitrogen don't like to live alone. They prefer to find another and stick together into a diatomic ( 2 atom ) molecule. Thus the molecular weight of atmospheric oxygen or nitrogen is approximately twice that of one of them alone. We say "approximately", because it takes energy to bind them together, and mass and energy are equivalent stuff, as our good friend Dr. Einstein explained with his famous equation E=MC2.