Is EMF Induced in a Square Loop Moving Through a Magnetic Field?

  • Thread starter Thread starter clementc
  • Start date Start date
  • Tags Tags
    Emf Induced
AI Thread Summary
When a square loop moves through a magnetic field at a constant velocity, no electromotive force (EMF) is induced because there is no change in magnetic flux through the loop, as per Faraday's law. In contrast, a straight wire moving through the same magnetic field induces EMF due to the increase in the area enclosed by an imaginary loop formed with the wire. The vertical sides of the square loop experience opposing forces on their charges, which effectively cancel each other out at the edges, preventing any net EMF. This distinction arises because the area of the square loop remains constant while it moves, unlike the straight wire scenario. Therefore, the induced EMF is dependent on the change in area or flux, which does not occur for the square loop.
clementc
Messages
38
Reaction score
2

Homework Statement


Hey guys,
This is just a qualitative question.
So assume I have a massive super large magnetic field, and pull a straight, isolated conducting wire sideways through it with constant velocity. I know that the EMF induced is given by
emf = Blv where
l is the length of the conductor
B the magnetic field strength
and v the velocity with which the wire moves

But say I have a square loop entirely in the field, and move it again with velocity v (it still remains entirely in the field)
Is there still emf induced? By Faraday's law, there's no change in flux, so hence there should be no emf. By I just don't know why.
I mean if emf is induced even for an isolated straight wire, why isn't it for a square loop?
I'm thinking it's kind of because the 2 vertical sides of the square loop both have charges trying to move up/down them (depending on the direction B and which way the loop moves), so they kind of "crash" into each other at the top and bottom edges and cancel out each other?
I'm sorry if it's kind of confusing, but does anyone know?

Thank you very much!
 
Physics news on Phys.org
when a straight wire moves, it behaves as though the area enclosed by an imaginary loop with the wire as one edge is increasing. but for a square loop, the area remains constant.
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top