Is f(x) = 2x Onto, One-to-One, or a Bijection for Different Domains?

AI Thread Summary
The discussion focuses on understanding the concepts of onto, one-to-one, and bijection functions using the example f(x) = 2x across different domains: integers (Z), naturals (N), and reals (R). The user seeks clarification on whether f(x) is onto, one-to-one, or a bijection for these specific sets. It is emphasized that grasping the definitions of these types of functions is crucial to solving the problem. The importance of applying these definitions to the given function and domains is highlighted as a way to deepen understanding. Overall, the thread aims to clarify these fundamental concepts in function analysis.
raross
Messages
12
Reaction score
0
Hey if anyone could help me with this I would be sooo grateful. I am trying to grasp the idea of onto, one-to-one and bijection(both) functions.

A sample problem is: If f(x) = 2x . What is f(Z), all integers. What is f(N), all naturals. What is f(R), all real. These are 3 different problems, and I am trying to figure out if they are onto, and/or one-to-one or bijection(which means both).

Any help would be a BIG HELP! Thanks!
 
Physics news on Phys.org
anyone?

anyone? Thanks
 
... =/
 
What is it you don't understand about one-to-one and onto functions?
 
Yeah, definitions are always the most important thing here. Type them up here and think about them for a bit and then we'll see what you're having trouble with.
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top