Is g(x)=5^sqrt(x) an Exponential Function?

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The discussion centers on whether the function g(x) = 5^sqrt(x) qualifies as an exponential function, defined as f(x) = ab^x. While g(x) resembles an exponential graph for x > 0, it is not continuous across all real numbers. The analysis suggests that for g(x) to match the form of an exponential function, it must satisfy specific conditions at key points, leading to the conclusion that g(0) = 1 and g(1) = 5. Ultimately, the graph of g(x) does not align with the standard exponential function f(x) = 5^x. Therefore, g(x) is not classified as an exponential function.
drewfstr314
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Our textbook defines an exponential function as
f(x) = ab^x. However, a question was brought up about a function, g(x) = 5^sqrt(x). Is g an exponential function? It looks like an exponential graph for x>0, but is not continuous on R.

Thanks in advance!
 
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A function is not defined in the absence of domain and range. So do tell us the whole definition as worded by your book.
 
drewfstr314 said:
Our textbook defines an exponential function as
f(x) = ab^x. However, a question was brought up about a function, g(x) = 5^sqrt(x). Is g an exponential function? It looks like an exponential graph for x>0, but is not continuous on R.

Let us ignore the fact that g(x) = 5^sqrt(x) is not always real-valued for negative x and ask the somewhat better defined question:

"Does the graph of g(x) = 5^sqrt(x) match the graph of any function f(x) of the form ab^x for real-valued constants a and b and positive real x"

One simple-minded way to answer this would be to assume that there is such a function and realize that, if so:

f(0) = a*b^0 = a = g(0) = 5^sqrt(0) = 1

So a = 1

f(1) = a*b^1 = ab = b = g(1) = 5^sqrt(1) = 5

So b = 5

So the question then becomes:

"does the graph of g(x) = 5^sqrt(x) match the graph of f(x) = 5^x"

The answer to that question is rather obvious.
 
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