- #1
newyorkcity
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How would I analyze the continuity of:
g(x,y) = sin(2x^2 - y^2) / 2x^2-y^2 unless y^2=2x^2
1 if y^2=2x^2
g(x,y) seems to be continuous for all values of (x,y)... However, I realize that the function assumes the value 0 when y^2=2x^2. I am not really sure how to go further than this... the function seems to be continuous, unless we specify that it assumes 1 when y^2=2x^2, which makes the function discontinuous.
Am I missing something?
g(x,y) = sin(2x^2 - y^2) / 2x^2-y^2 unless y^2=2x^2
1 if y^2=2x^2
g(x,y) seems to be continuous for all values of (x,y)... However, I realize that the function assumes the value 0 when y^2=2x^2. I am not really sure how to go further than this... the function seems to be continuous, unless we specify that it assumes 1 when y^2=2x^2, which makes the function discontinuous.
Am I missing something?
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