Rap said:
I think net force implies work. I cannot think of anything which, when subjected to a net force, does not move, except an infinitely massive object.
Again, you're right; but again you're taking a jump in logic by saying that that supports your argument that energy is expended by the forces on a stationary object. What you said is correct: if an object is subjected to a net or unbalanced force, it will move. Then work will have been done on the object, which is also equal to the energy expended. Great. The problem is, that's pretty much irrelevant to the point you're arguing. I said that work implies force, but force does not imply work. You countered by adding the word "net" in front of the force, which is a completely different argument.
Your argument only holds true for net, or
imbalanced forces, like in the case of a rocket. In the case of a stationary box, the forces are
balanced, (i.e. \vec{F_{net}} = 0), but that doesn't mean there are no forces involved. There is still force (gravitational force pulling down, and an equal supporting force pushing up) but the net force is 0, so the object will not move. In that case, no work is done, because the object has not moved at all (use your F*d formula for an unmoving object if you don't believe me). There are
tons of cases like this. (Ask any engineer taking a statics class, which I am right now). In the case where the NET force equals zero (again, this is NOT equivalent to saying there is no force applied), there is no mechanical work done, and therefore there is no energy transfer.
Edit: Oops, I thought that was the OP replying. Still, my point stands. You can't use work done by imbalanced forces to argue that work is done by balanced forces. Work implies force (imbalanced force, in fact), but force, particularly balanced force, does not imply work. Balanced forces is what we're talking about with an unmoving box, not imbalanced forces. The argument that imbalanced forces create work is true but irrelevant in this case.