Kenai
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Hey guys,
I was wondering if this reactions is possible:
\pi^{+} + n \rightarrow p + \gamma
(Assuming there is enough energy in the initial state to make the reaction go)
If not, what law is violated?
Lepton and baryon numbers are ok... also angular momentum, so I guess it's possible, but still... I can't figure out how to draw the feynman diagram, since there is a total of 5 quarks in the initial state (u,\bar{d}... d,d,u) and there is just 3 in the final state (u,u,d and gamma).
At first, I was thinking in merging d and \bar{d} into a photon , but just 1 photon would violate the momentum conservation law...
Any ideas?
Thanks
I was wondering if this reactions is possible:
\pi^{+} + n \rightarrow p + \gamma
(Assuming there is enough energy in the initial state to make the reaction go)
If not, what law is violated?
Lepton and baryon numbers are ok... also angular momentum, so I guess it's possible, but still... I can't figure out how to draw the feynman diagram, since there is a total of 5 quarks in the initial state (u,\bar{d}... d,d,u) and there is just 3 in the final state (u,u,d and gamma).
At first, I was thinking in merging d and \bar{d} into a photon , but just 1 photon would violate the momentum conservation law...
Any ideas?
Thanks
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