Is It Possible to Have an Imaginary Normalisation Constant?

AI Thread Summary
The discussion centers on determining the normalization constant C for a one-dimensional quantum system described by a superposition of two energy eigenfunctions, Q1(x) and Q2(x). The participant initially calculates C as i(1.2)^0.5, leading to confusion about the possibility of an imaginary normalization constant. It is clarified that the integral of the squared total wavefunction must equal one, and due to the orthogonality of the eigenfunctions, the integral of Q1(x)Q2*(x) is zero. Ultimately, the correct normalization condition results in C^2 equating to 5/20, confirming that the imaginary value for C is not valid in this context. The discussion emphasizes the importance of correctly applying the principles of quantum mechanics, particularly linear superposition and orthogonality of eigenstates.
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Homework Statement



A one-dimensional system is in a state at time t=0 represented by:

Q(x) = C { (1.6^0.5)Q1(x) - (2.4^0.5)Q2(x)}

Where Qn(x) are normalised eergy eigenfunctions corresponding to different energy eigenvalues, En(n=1,2)

Obtain the normalisation constant C


The Attempt at a Solution



I get C= i(1.2)^0.5 from the following equation:

C^2 * (1.6 (int( Q1 ^2 dx) - 2.4(int ( Q2 ^2 dx = 1

So C^2 has to be -5/4 in order for the above to be true. Is this right?
Just a bit confused over whether it's possible to have an imaginary value for the normalisation constant? Thanks for any help you can give.
 
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You haven't formed the product Q(x)Q*(x) correctly. What is special about energy eigenstates?
 
they follow linear superposition? so the integral of the total wavefunction squared is equal to the integral of 1.6*Q1^2 plus the integral of 2.4*Q2^2?
 
What is Q* equal to ? How do you define the scalar product?

Daniel.
 
Well there aren't any imaginary parts to the first wavefunction since its just in the form Q = C ( XQ1 - YQ2) so Q* is just the same as Q.
 
Ruddiger27 said:
they follow linear superposition?
What do you know about the integral of Q1Q2*?

so the integral of the total wavefunction squared is equal to the integral of 1.6*Q1^2 plus the integral of 2.4*Q2^2?
Yes. Are you absolutely clear why this is so?
 
I would think the integral of Q1Q2* would be zero since these wavefunctions are orthogonal, so I would end up with C^2 =5/20.
 
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